1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Shalnov [3]
3 years ago
8

How does the composition of a comet compare with that of the Sun?

Physics
1 answer:
slamgirl [31]3 years ago
7 0

Answer:

C

Explanation:

You might be interested in
What is the force on a 52 coulomb charge in a field of 5 N/C
slega [8]
Https://courses.physics.illinois.edu/phys102/sp2013/lectures/lecture2.pdf



Check out upload.
Download pdf
8 0
3 years ago
Difference between power ciruit and light circuit?
Svetlanka [38]

Refer to attachment for your answer

7 0
2 years ago
In being served, a tennis ball is accelerated from rest to a speed of 31.6 m/s. The average power generated during the serve is
joja [24]

Answer:

The force acting on the ball is 92.4 N.

Explanation:

Given that,

Initial speed of the ball, u = 0

Final speed of the ball, v = 31.6 m/s

The average power generated during the serve is 2920 W. Power generated by an object is given by :

P=\dfrac{W}{t}

W is the work done, W = Fd

P=\dfrac{Fd}{t}

Since, v=\dfrac{d}{t}

So,

P=F\times v

F is the force acting on the ball

F=\dfrac{P}{v}\\\\F=\dfrac{2920\ W}{31.6\ m/s}\\\\F = 92.4\ N

So, the force acting on the ball is 92.4 N. Hence, this is the required solution.

7 0
3 years ago
A boxer punches a sheet of paper in midair and brings it from rest up to a speed of 30 m/s in 0.060 s .
zimovet [89]

Answer:

Force exerted, F = 1.5 N

Explanation:

It is given that, a boxer punches a sheet of paper in midair and brings it from rest up to a speed of 30 m/s in 0.060 s.

i.e. u = 0

v = 30 m/s

Time taken, t = 0.06 s

Mass of the paper, m = 0.003 kg

We need to find the force the boxer exert on it. The force can be calculated using second law of motion as :

F=m\times a

F=m\times (\dfrac{v-u}{t})

F=0.003\times (\dfrac{30}{0.06})

F = 1.5 N

So, the force the boxer exert on the paper is 1.5 N. Hence, this is the required solution.

6 0
3 years ago
Hydrogen has only one electron in its only (and outer) electron shell. If a hydrogen atom were to absorb a small amount of energ
Xelga [282]

Answer:

D. move up to another shell that would form

Explanation:

An atom has protons, neutrons and electrons. Protons and neutrons are present in the nucleus and electrons orbit the nucleus in fixed shells. An electron can jump to higher shell when it gains energy and lower one when it loses energy. Thus, when single electron in hydrogen atom is given a small amount of energy, it would jump to another higher shell.

8 0
3 years ago
Other questions:
  • How much energy is used by a 900 w microwave that operates for 4 minutes ?
    6·1 answer
  • Which of the following is a unit of volume of solids?
    13·2 answers
  • The boom of a fire truck raises a fireman (and his equipment – total weight 280 lbs) 60 ft into the air to fight a building fire
    6·1 answer
  • A dolphin's tops speed is 17 m/s. If a dolphin swam at this constant velocity for one hour
    7·1 answer
  • When monochromatic light passes through the interface between two unknown materials at an angle θ where 0∘<θ<90∘, no chang
    6·1 answer
  • If a 8.0 kg mass is hung on the end of a spring, it is stretched 0.78 meters as a result. What is the force constant of the spri
    6·2 answers
  • A runner sprints around a circular track of radius 130 m at a constant speed of 7 m/s. The runner's friend is standing at a dist
    11·1 answer
  • (II) A sled is initially given a shove up a frictionless 23.0° incline. It reaches a maximum vertical height 1.22 m higher than
    5·1 answer
  • What is the name of type of relationship that exists between wavelength and frequency ?
    6·1 answer
  • Why can’t we see the molecules moving in a solid or liquid?
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!