Question

A roll of kitchen aluminum foil is 30 cm wide by 22 m long (if you unroll it). If the foil is 0.15 mm thick, and the specific weight of aluminum is 26460 N/m3, how much does the roll of aluminum foil weigh

Answer 1

The weight of the aluminum foil is 26.20 N

To find the weight of the aluminum foil when it is unrolled, we need to find its volume.

The volume V = lwt where

• l = length of aluminum foil = 22 m,
• w = width of aluminum foil = 30 cm = 0.30 m and
• t = thickness of aluminum foil = 0.15 mm = 0.15 × 10⁻³ m.

So, V = lwt

= 22 m × 0.30 m × 0.15 × 10⁻³ m

= 0.99 × 10⁻³ m³.

So, its weight W = ρV where

• ρ = specific weight of aluminum = 26460 N/m³ and
• V = volume of aluminum foil = 0.99 × 10⁻³ m³

So, W = ρV

W = 26460 N/m³ × 0.99 × 10⁻³ m³

W = 26195.4 × 10⁻³ N

W = 26.1954 N

W ≅ 26.20 N

So, the weight of the aluminum foil is 26.20 N

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