The weight of the aluminum foil is 26.20 N
To find the weight of the aluminum foil when it is unrolled, we need to find its volume.
The volume V = lwt where
- l = length of aluminum foil = 22 m,
- w = width of aluminum foil = 30 cm = 0.30 m and
- t = thickness of aluminum foil = 0.15 mm = 0.15 × 10⁻³ m.
So, V = lwt
= 22 m × 0.30 m × 0.15 × 10⁻³ m
= 0.99 × 10⁻³ m³.
So, its weight W = ρV where
- ρ = specific weight of aluminum = 26460 N/m³ and
- V = volume of aluminum foil = 0.99 × 10⁻³ m³
So, W = ρV
W = 26460 N/m³ × 0.99 × 10⁻³ m³
W = 26195.4 × 10⁻³ N
W = 26.1954 N
W ≅ 26.20 N
So, the weight of the aluminum foil is 26.20 N
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