The phenolphthalein indicator changes color close to the point9f neutralization which shows the end-point of the titration

OleMash [197]

The mass of electrons , i just did the same test and got it right

7 0

3 years ago

Each of the chemically active Period 2 elements forms stable compounds in which it has bonds to fluorine.(a) What are the names

Softa [21]

The names of the compound are lithium fluoride ( LiF) , beryllium difluoride (BeF2) , Boron trifluoride (BF3) , carbon tetrafluoride (CF4) , nitrogen trifluoride (NF3) , oxygen difluoride (OF2) .

Lithium is the first element of period 2 which reacts with fluorine to form LiF ( lithium fluoride ) . it is an inorganic compound . it is also a colorless solid . it is less soluble in water . it is chemically stable because of its comparable molecular mass .

Beryllium is the second element of period 2 which reacts with fluorine to give beryllium difluoride (BeF2) . it is inorganic compound . it is highly soluble in water. it is also a stable compound . it have low melting point .

Boron is the third element of period 2 which reacts with fluorine to form

BF3 (Boron trifluoride ) . it is a inorganic compound . it is colorless and toxic gas forms . it is stable in dry atmosphere but its octet is not satisfied .

Carbon is the 4th element of the period 2 which reacts with fluorine to form carbon tetrafluoride (CF4) . it is not soluble in water . it is a greenhouse gas . it dissolves in oil. it is very stable compound .it forms covalent bond .

Nitrogen is the 5th element of period 2 which reacts with fluorine to form nitrogen trifluoride (NF3) . it is also a inorganic compound . it is colorless and non-flammable . it is a stable gas at room temperature .

Oxygen is the 6th element of period 2 which reacts with fluorine to form oxygen difluoride (OF2) . it is colorless poisonous gas . it is partially stable or relatively stable .

Neon is a noble gas and also a stable element . it is odorless and colorless . so it is nonreactive . so it doesn't form bond with fluorine .

<h3>Learn more about Fluorine here :</h3>

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8 0

2 years ago

How many calories are required to convert 17 g of ice at 0.0Â°C to liquid water at 32.0Â°C? The heat of fusion of water is 80. c

Mazyrski [523]

Answer : The heat required is, 1904 calories.

Explanation :

The process involved in this problem are :

$(1):H_2O(s)(0^oC)\rightarrow H_2O(l)(0^oC)\\\\(2):H_2O(l)(0^oC)\rightarrow H_2O(l)(32.0^oC)$

The expression used will be:

$\Delta H=m\times \Delta H_{fusion}+[m\times c_{p,l}\times (T_{final}-T_{initial})]$

where,

m = mass of ice = 17 g

$c_{p,l}$ = specific heat of liquid water = $1cal/g^oC$

$\Delta H_{fusion}$ = enthalpy change for fusion = $80.0cal/g$

Now put all the given values in the above expression, we get:

$\Delta H=17g\times 80.0cal/g+[17g\times 1cal/g^oC\times (32.0-0)^oC]$

$\Delta H=1904cal$

Therefore, the heat required is, 1904 calories.

3 0

4 years ago

Carbon can bond with other carbon atoms to produce cyclic hydrocarbon structures.

Bad White [126]

The statement about "Carbon can bond with other carbon atoms to produce cyclic hydrocarbon structures" is true. <span>Carbon can also bond with other four atoms because of its outer shell (valence shell) that has four electrons. This is the reason why organic molecules can be so large because of this bonding. </span>

3 0

3 years ago

Read 2 more answers

Which of the following wave types has a wavelength closest to visible light?

Dominik [7]

I belive its b
hope this helps :)

3 0

3 years ago

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