Answer:
15.65 MPa 150 times of human body internal pressure
Explanation:
Given:
- Depth of the ocean for offshore drilling d = 1 mile
Find:
Determine the pressure at that location
What would happen to an unprotected, exposed person at that depth?
Solution:
- The pressure at a certain depth of a fluid can be calculated with:
P = p_w*g*d
Where, P is the pressure , p_w is the density of water ( 997 kg / m^3 ).
- Hence @ d = 1.0 mile = 1.6 km = 1600 m:
P = 997*9.81*1600
P = 15.65 MPa
- Whereas the pressure inside a human body is 101 KPa, Pressure under ocean @ 1 mile of depth is 150 times in magnitude, enough to crush the human body!
<h3>
Option A</h3>
In a Series circuit with two identical loads, the voltage across each load will be: the same
<h3><u>
Explanation:</u></h3>
A series circuit is one with total the loads in a row. There is barely ONE path for electricity to pass. If this circuit was a series of flashbulbs, and one left out, the left bulbs would switch off. T
he current in a series circuit is universally the same and the voltage over the circuit is the amount of the unique voltage drops over each component. The voltage referred to as a series circuit is equivalent to the amount of the individual voltage drops.
Answer:
Part A:
Hourly production rate of acceptable parts=9.525 parts/hr
Part B:
Scrap rate=0.042713=4.2713%
Part C:
Proportion uptime=0.9774215=97.74215%
Explanation:
Part A:
Acceptable (non-defective) parts=381
Hours Per week=40
Hourly production rate of acceptable parts=Acceptable (non-defective) parts/Hours Per week
Hourly production rate of acceptable parts=![\frac{381}{40}](https://tex.z-dn.net/?f=%5Cfrac%7B381%7D%7B40%7D)
Hourly production rate of acceptable parts=9.525 parts/hr
Part B:
Total Parts Produced=Non-defective parts-Defective parts
Total Parts Produced=381+17
Total Parts Produced=398
Scrap rate=17/398
Scrap rate=0.042713=4.2713%
Part C:
Total Time for operation=5.23+0.58+(
)
Total Time for operation=5.894 min
Total up time=398(5.894)=2345.812 min=39.09686 hr
Proportion uptime=![\frac{39.09686}{40}](https://tex.z-dn.net/?f=%5Cfrac%7B39.09686%7D%7B40%7D)
Proportion uptime=0.9774215=97.74215%
The correct answer to your problem is the answers of a and b
Given Information:
Temperature = T₁ = 50 °C
Mass flow rate = m = 30 kg/s
Exit Pressure = P₂ = 1.5 MPa = 1500 kPa
Required Information:
Power = P = ?
Answer:
Power = 45.16 kW
Explanation:
The power of the pump can be found using,
P = m*W
Where m is the mass flow rate and W is the work done by pump.
Work done is given by
W = vf*(P₂ - P₁)
Where vf is the specific volume and its value is found from the saturated water temperature table.
at T = 50 °C
vf = 0.001012 m³/kg
P₁ = 12.352 kPa
P = m*W
P = m*vf*(P₂ - P₁)
P = 30*0.001012*(1500 - 12.352)
P = 45.16 kW