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bonufazy [111]
3 years ago
14

This means divide or to take apart the pieces. ( science )

Physics
1 answer:
zavuch27 [327]3 years ago
8 0

Answer:

disassemble, break apart,divide, separate

Explanation:

just know and have learned it....

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A truck accelerating at 0.0083 meters/second2 covers a distance of 5.8 × 104 meters. If the truck's mass is 7,000 kilograms, wha
zhannawk [14.2K]
Work done = force * distance moved (in direction of the force)

force= mass* acceleration 

force=58.1N

58.1*(5.8*10^4)
=3,369,800 J
7 0
3 years ago
Read 2 more answers
The intensity level is 65 db at a distance 5.00 m from a barking dog. What would be a reasonable estimate for the intensity leve
BARSIC [14]

Answer:

68 db

Explanation:

Since now instead of one two dogs are barking simultaneously close to each other, therefore we take n =2.

Ignoring interference effects, the barking of two dogs result in a higher level of intensity which is given by,

β(db)=10×㏒(2)

=3 db

So, a reasonable estimate for the raised Intensity Level is: 65db+3db = 68db

7 0
3 years ago
A charge Q is transferred from an initially uncharged plastic ball to an identical ball 10.0 cm away. The force of attraction is
victus00 [196]

Answer:

a charge Q is transferred from an initially uncharged

Explanation:

Hope this helps!

5 0
2 years ago
A train travels a distance of 2000 km at an average speed of 120 km per hour. How long did the trip take? SHOW WORK
Igoryamba
S = d/t, s = 120, d = 2000, t = ?
Input the values,
120 = 2000/t
Make t the subject of the formula by cross multiplying, Therefore,
120t = 2000
Divide both sides by 120
t = 16.7hrs  to 1 decimal place.
If you're asked to convert it, you can.


6 0
3 years ago
Ben rushin is waiting at a stoplight. when it finally turns green, ben accelerated from rest at a rate of a 6.00 m/s2 for a time
jasenka [17]

In the 4.10 seconds that elapsed, Ben reaches a velocity of

v_f=v_0+at\implies v_f=0\,\dfrac{\mathrm m}{\mathrm s}+\left(6.00\,\dfrac{\mathrm m}{\mathrm s^2}\right)(4.10\,\mathrm s)

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In this time, his displacement \Delta x satisfies

{v_f}^2-{v_0}^2=2a\Delta x\implies\left(24.6\,\dfrac{\mathrm m}{\mathrm s}\right)^2-\left(0\,\dfrac{\mathrm m}{\mathrm s}\right)^2=2\left(6.00\,\dfrac{\mathrm m}{\mathrm s^2}\right)\Delta x

\implies\Delta x=50.4\,\mathrm m

4 0
3 years ago
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