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Juli2301 [7.4K]
4 years ago
13

Which is not a step in the scientific method?

Physics
1 answer:
MatroZZZ [7]4 years ago
3 0
C because

You have to have a question then research and arrive to a conclusion
You might be interested in
1. A 20m steel wire is stretched to 20.0m by
Eduardwww [97]

Answer:

Force to stretch the wire is 250 N

Explanation:

As we know that modulus of elasticity will remain the same for the wire if the applied stretch to the wire is within elastic limit

So we will have

\frac{F L}{\Delta L A} = constant

now we have

\frac{F_1 L}{\Delta L_1 A} = \frac{F_2 L}{\Delta L_2 A}

so we can write it as

F_2 = \frac{F_1 L_2}{L_1}

F_2 = \frac{50 (0.05)}{0.01}

F_2 = 250 N

7 0
3 years ago
Which is the direction of in stantaneous velocity for angular path
Alexandra [31]

<em>Answer:</em>

<em>Right hand rule</em>

<em>Explanation:</em>

<em>The rule by which the direction of a rotational vector can be found: take your right hand, curl your fingers and stick your thumb straight up. If you let the curl of your fingers follow the path of the rotating particle or body, your thumb will point in the direction of the angular velocity of the body.</em>

3 0
3 years ago
Water flows over a section of Niagara Falls at a rate of 2.2 × 106 kg/s and falls 65 m. What is the power wasted by the waterfal
Irina-Kira [14]

Answer:

P = 1401.4 x 10⁶ W

Explanation:

Given that

Water flow rate m = 2.2 x 10⁶ kg/s

Height ,h= 65 m

Acceleration due to gravity ,g= 9.8 m/s²

The power P is given as

P= m g h

P=Power

m=Water flow rate

h=height

Now by putting the values in the above equation

P = 2.2 x 10⁶ x 9.8 x 65 W

P = 1401.4 x 10⁶ W

Therefore the power wasted will be 1401.4 x 10⁶ W.

7 0
3 years ago
A 62.5 kg carpenter at a construction site plans to swing in a circular arc from one roof top to an adjacent roof at the end of
denis23 [38]

Answer:

    v = 9.45 m/s

Explanation:

given,

mass of the carpenter = 62.5 Kg

length of rope = 13.4 m

Capable of exerting force = 1034 N

centripetal force acting on the body

                   F = \dfrac{mv^2}{r}

                   F = \dfrac{62.5\times v^2}{13.4}

                  F =4.664 v²  N

Gravitational force on her =

                  F = m g

                  F = 62.5 x 9.81

                  F = 613.125 N

now,

4.664 v² + 613.125 = 1034

4.664 v² = 420.875

   v²  = 90.24

    v = 9.45 m/s

Maximum speed which she can tolerate = v = 9.45 m/s

7 0
3 years ago
If a fixed length simple pendulum is found to have three times the period on an unknown planet’s surface (compared to Earth), wh
balu736 [363]

Answer:

g/9

Explanation:

length of the pendulum = L

time period on the earth = T

Time period on the planet = 3T

Let the acceleration due to gravity on the earth is g and on the planet is g'.

Use the formula for the time period of a simple pendulum for the time period on earth

T=2\pi \sqrt{\frac{L}{g}}     .... (1)

Time period on the surface of planet is

3T=2\pi \sqrt{\frac{L}{g'}}      .... (2)

Divide equation (2) by equation (1)

\frac{3T}{T}= \sqrt{\frac{g}{g'}}

g' = g/9

Thus, the acceleration due to gravity on the planet is g /9

6 0
3 years ago
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