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Alex_Xolod [135]
3 years ago
15

Pls help me will mark brainliest, chemistry equilibrium!!!

Chemistry
1 answer:
Sergeeva-Olga [200]3 years ago
3 0

Answer:

See attached => LeChatelier's Principle

Explanation:

LeChatelier's Principle => If a stress is applied to a chemical reaction, the reaction chemistry will shift away from the applied stress and establish a new equilibrium having new concentration values different from the original concentration values.

There are three (3) principle stress factors that will cause disturb a chemical reaction and cause it to shift to establish a new equilibrium. These are ...

=> concentration effects,

=> temperature effects, and

=> pressure-volume effects.

The attached notes explain in general terms how to evaluate a chemical reaction under an applied stress factor and determine direction of shift to establish a new equilibrium stability. Compare and apply to the worksheet problems.

_______

Answers to worksheet (compare to attached notes)

1a. => increasing wt to product side => tilts right => shifts left

1b. => removing wt from reactant side => tilts right => shifts left,

1c. => increasing wt to product side => tilts right => shifts left

2a. => tilts left (excess wt from Hg), shifts right,

2b. => Increase pressure shifts toward lower molar gas volume side (right) Note: apply only to gas phase substances, Hg is in liquid phase.

3a. exothermic rxn => cooling => tilts left, rxn shifts right

3b. endothermic rxn => cooling => tilts right, rxn shifts left

3c. exothermic rxn => cooling => tilts left, rxn shifts right

_____________

don't forget => brainliest :-)

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hodyreva [135]

Answer:

122.3 g of Fe₂O₃ is the maximum amount formed

Explanation:

Our reactants for the reaction:

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We convert the mass of each to moles:

89.5 g of Fe . 1 mol / 55.85 g = 1.60 moles

36.9 g of O₂ . 1mol / 32g = 1.15 moles

The reaction is  4Fe(s) + 3O₂(g) →  2Fe₂O₃ (s)

We determine the limiting reactant:

4 moles of Iron can react with 3 moles of O₂

Therefore 1.60 moles of Iron will react with (1.60 .3) / 4 = 1.2 moles

Oxygen is the limiting reactant; we need 1.2 moles, and we only have 1.15.

Then we work with the stoichiometry again.

3 moles of oxygen can produce 2 moles of Fe₂O₃

1.15 moles of oxygen may produce (1.15 . 2) / 3 = 0.766 moles of Fe₂O₃

We convert the moles to mass: 0.766 mol . 159.7 g /1mol = 122.3 g of Fe₂O₃

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Hence, first we will calculate the value of pK_{a} as follows.

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