Answer: The energy (heat) required to convert 52.0 g of ice at –10.0°C to steam at 100°C is 157.8 kJ
Explanation:
Using this formular, q = [mCpΔT] and = [nΔHfusion]
The energy that is needed in the different physical changes is thus:
The heat needed to raise the ice temperature from -10.0°C to 0°C is given as as:
q = [mCpΔT]
q = 52.0 x 2.09 x 10
q = 1.09 kJ
While from 0°C to 100°C is calculated as:
q = [mCpΔT]
q = 52.0 x 4.18 x 100
q = 21.74 kJ
And for fusion at 0°C is called Heat of fusion and would be given as:
q = n ΔHfusion
q = 52.0 / 18.02 x 6.02
q = 17.38 kJ
And that required for vaporization at 100°C is called Heat of vaporization and it's given as:
q = n ΔHvaporization
q = 52.0 / 18.02 x 40.7
q = 117.45 kJ
Add up all the energy gives 157.8 kJ
A. A diagram showing the effects of temperature and pressure on phase
Explanation:
A phase diagram is a diagram that shows the effects of temperature and pressure on phase.
- A phase diagram shows how different substances are transformed from one form to another.
- The transformation is an interplay between pressure and temperature.
- The phase graph represents physical state changes.
- A phase change is made up of pressure on the y-axis and temperature on the x - axis.
Learn more:
Phase change brainly.com/question/1875234
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.energy mechanical needs it Answer:
Yes.
Explanation:
