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Maurinko [17]
3 years ago
13

How many moles of ethanol C2H6O, are in a 10.0g sample​

Chemistry
1 answer:
Brrunno [24]3 years ago
6 0

Answer: 0.217 mol

Explanation:

To find the amount of moles in a 10 g sample, we need the molar mass of ethanol.

Molar Mass: 46.07 g/mol

Now that we have the molar mass, we can find moles.

10.0 g*\frac{1mol}{46.07g}=0.217 mol

We know that there are 0.217 mol in a 10.0 gram sample.

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If 354.2g PbCl2 are reacted with excess Na3PO4, how many grams of NaCl will be produced
Illusion [34]

Answer: The mass of NaCl produced is, 149 grams.

Explanation : Given,

Mass of PbCl_2 = 354.2 g

Molar mass of PbCl_2 = 278 g/mol

Molar mass of NaCl = 58.5 g/mol

First we have to calculate the moles of PbCl_2

\text{Moles of }PbCl_2=\frac{\text{Given mass }PbCl_2}{\text{Molar mass }PbCl_2}

\text{Moles of }PbCl_2=\frac{354.2g}{278g/mol}=1.27mol

Now we have to calculate the moles of CaCl_2

The balanced chemical equation is:

3PbCl_2+2Na_3PO_4\rightarrow 6NaCl+Pb_3(PO_4)_2

From the reaction, we conclude that

As, 3 moles of PbCl_2 react to give 6 mole of NaCl

So, 1.27 moles of PbCl_2 react to give \frac{6}{3}\times 1.27=2.54 mole of NaCl

Now we have to calculate the mass of NaCl

\text{ Mass of }NaCl=\text{ Moles of }NaCl\times \text{ Molar mass of }NaCl

\text{ Mass of }NaCl=(2.54moles)\times (58.5g/mole)=148.59g\approx 149g

Therefore, the mass of NaCl produced is, 149 grams.

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