Answer: 7.2 ounces
Explanation:
1) Data:
<span>- glass size: 9-ounce
</span><span>
</span><span>- content of vitamin C: 72 milligrams
</span><span>
</span><span>
</span><span>- glasssize: x
</span><span>
</span><span>- content of vitamin C: 60 milligrams
</span><span>
</span><span>
</span><span>2) Proportion
</span><span>
</span><span>
</span><span>9 ounces / 75 mg = x / 60 mg
</span><span>
</span><span>
</span><span>3) Solution:
</span><span>
</span><span>
</span><span>9 ounces × 60 mg = 75 mg × x
</span><span>
</span><span>
</span><span>⇒ x = 9 ounces × 60 mg / 75 mg = 7.2 ounces
</span>
Answer:
The new concentration is 0.125 M.
Explanation:
Given data:
Initial volume V₁ = 125.0 mL
Initial molarity M₁ = 0.150 M
New volume V₂ = 25 mL +125 mL = 150 mL
New concentration M₂ = ?
Solution:
M₁V₁ = M₂V₂
0.150 M × 125 mL = M₂ × 150 mL
M₂ = 0.150 M × 125 mL / 150mL
M₂ = 18.75 M.mL/150 mL
M₂ = 0.125 M
The new concentration is 0.125 M.
The statement that defines the specific heat capacity for a given sample is the quantity of heat that is required to raise 1 g of the sample by 1°C (Kelvin) at a constant pressure.
<h3>What is specific heat capacity?</h3>
Specific heat capacity is the of heat to increase the temperature per unit mass.
The formula to calculate the specific heat is Q = mct.
The options are attached here:
- The temperature of a given sample is 1 %.
- The temperature that a given sample can withstand.
- The quantity of heat that is required to raise the sample's temperature by 1 °C1 °C (Kelvin).
- The quantity of heat that is required to raise 1 g of the sample by 1°C (Kelvin) at a constant pressure.
Thus, the correct option is 4. The quantity of heat that is required to raise 1 g of the sample by 1°C (Kelvin) at a constant pressure.
Learn more about specific heat capacity
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Answer:
Postassium bisulphate - KHSO4 - can be used as an food preservative to protect the food from micro-organisms.
