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ohaa [14]
3 years ago
12

What is the mass in grams of a 8.4 mole sample of iron?

Chemistry
2 answers:
wlad13 [49]3 years ago
5 0
8.4 moles equals 469.14g Fe
Nikolay [14]3 years ago
4 0

Answer:

mass in grams of 8.4 mole of Fe = 469.098  grams

Explanation:

Iron is a metal substance. The molecular mass of Iron is 55.845 gram. This means 1 mole of Iron substance contains 55.845 grams.

The chemical formula of Iron is Fe.

Atomic mass of Iron = 55.845 g

Since, 1 mole of Iron is 55.845 g

8.4 mole is ?

cross multiply

mass in grams of 8.4 mole of Fe = 8.4 × 55.845/1

mass in grams of 8.4 mole of Fe = 8.4 × 55.845/1

mass in grams of 8.4 mole of Fe = 469.098  grams

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2 years ago
Element Molar Mass (g/mol)
artcher [175]

The number of moles of ethanol the chemist will use in the experiment involving 30g of ethanol is 0.65moles.

<h3>How to calculate number of moles?</h3>

The number of moles of a substance can be calculated by dividing the mass of the substance by its molar mass. That is;

no. of moles = mass ÷ molar mass

According to this question, a chemist will use a sample of 30 g of ethanol (CH3CH2OH) in an experiment. The number of moles can be calculated as follows:

Molar mass of ethanol = 12(2) + 1(5) + 17 = 46g/mol

no of moles = 30g ÷ 46g/mol

no. of moles = 0.65moles

Therefore, the number of moles of ethanol the chemist will use in the experiment involving 30g of ethanol is 0.65moles.

Learn more about moles at: brainly.com/question/1458253

6 0
2 years ago
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Which of the following is an inorganic compound?<br> AgNO3<br> C6H12<br> СНОН<br> C₂H7N
Lemur [1.5K]

Answer:

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4 0
3 years ago
50 ml of 0.2 M acetic acid is shaken with 10 g activated charcoal. The concentration of acetic acid is reduced to 0.5 times the
Olegator [25]

Answer:

0.03 g_{acid}/g_{charcoal}

Explanation:

The amount adsorbed (solute) is the acetic acid, and the adsorbent is the activated charcoal. The mass of the adsorbent is 10 g.

So, we need to calculate the mass of the acetic acid as follows:

m = n*M = C*V*M

Where:

n: is the number of moles = C*V

M: is the molecular mass =  60.052 g/mol

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Therefore, the amount of solute adsorbed per gram of the adsorbent is 0.03 g/g.

I hope it helps you!

3 0
3 years ago
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