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ohaa [14]
3 years ago
12

What is the mass in grams of a 8.4 mole sample of iron?

Chemistry
2 answers:
wlad13 [49]3 years ago
5 0
8.4 moles equals 469.14g Fe
Nikolay [14]3 years ago
4 0

Answer:

mass in grams of 8.4 mole of Fe = 469.098  grams

Explanation:

Iron is a metal substance. The molecular mass of Iron is 55.845 gram. This means 1 mole of Iron substance contains 55.845 grams.

The chemical formula of Iron is Fe.

Atomic mass of Iron = 55.845 g

Since, 1 mole of Iron is 55.845 g

8.4 mole is ?

cross multiply

mass in grams of 8.4 mole of Fe = 8.4 × 55.845/1

mass in grams of 8.4 mole of Fe = 8.4 × 55.845/1

mass in grams of 8.4 mole of Fe = 469.098  grams

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A student wants to remove the salt from a mixture of sand and salt in order to get only pure sand. He adds water to the mixture.
raketka [301]

Answer:

Here is one way: Add water to the mixture. Only the sugar dissolves. This is a physical change.

Explanation:

The sugar would dissolve in water. You could then pour off the solution and wash the remaining sand with a bit more water. Heat the water to evaporate it from the sugar, and the two are separated.

5 0
3 years ago
Read 2 more answers
What is bias in an experiment?
11111nata11111 [884]
I’m not sure what the answer is but I hope someone can help you
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3 years ago
A first-order reaction is 45% complete at the end of 43 minutes. What is the length of the half-life of this reaction
shtirl [24]

The half-life of the reaction is 50 minutes

Data;

  • Time = 43 minutes
  • Type of reaction = first order
  • Amount of Completion = 45%

<h3>Reaction Constant</h3>

Let the initial concentration of the reaction be X_0

The reactant left = (1 - 0.45) X_0 = 0.55 X_0 = X

For a first order reaction

\ln(\frac{x}{x_o}) = -kt\\ k = \frac{1}{t}\ln (\frac{x_o}{x}) \\ k = \frac{1}{43}\ln (\frac{x_o}{0.55_o})\\ k = 0.013903 min^-^1

<h3>Half Life </h3>

The half-life of a reaction is said to be the time required for the initial amount of the reactant to reach half it's original size.

x = \frac{x_o}{2} \\t = t_\frac{1}{2} \\t_\frac{1}{2} = \frac{1}{k}\ln(\frac{x_o}{x_o/2})\\

Substitute the values

t_\frac{1}{2} = \frac{1}{k}\ln(2)=\frac{0.6931}{0.013903}\\t_\frac{1}{2}= 49.85 min = 50 min

The half-life of the reaction is 50 minutes

Learn more on half-life of a first order reaction here;

brainly.com/question/14936355

4 0
2 years ago
The ionization of pure water forms _____.
Evgesh-ka [11]

Answer: The ionization of pure water forms <u><em>hydroxide and hydronium ions.</em></u>

Explanation:

Ionization is a reaction in the pure water in which water breaks down into its constituting ions that hydronium ion and hydroxide ions.

H_2O+H_2O\rightleftharpoons H_3O^++OH^-

One molecule of water looses its proton to form hydroxide ion and l=the lost protons get associated with another water molecule to form hydronium ion.

4 0
3 years ago
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kirill [66]
Well,





I guess the answer would be....


























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3 years ago
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