Once you have identified the limiting reactant, you calculate how much of the other reactant it must have reacted with and subtract from the original amount.
Answer:

Explanation:
In this case, we can start with the reaction:

If we check the reaction, we will have 2 X and Y atoms on both sides. So, <u>the reaction is balanced</u>. Now, the problem give to us two amounts of reagents. Therefore, we have to find the <u>limiting reagent</u>. The first step then is to find the moles of each compound using the <u>molar mass</u>:


Now, we can <u>divide by the coefficient</u> of each compound (given by the balanced reaction):


The smallest value is for "X", therefore this is our <u>limiting reagent</u>. Now, if we use the <u>molar ratio</u> between "X" and "XY" we can calculate the moles of XY, so:

Finally, with the molar mass of "XY" we can calculate the grams. Now, we know that 1 mol X = 85 g X and 1 mol
= 48 g
(therefore 1 mol Y = 24 g Y). With this in mind the <u>molar mass of XY</u> would be 85+24 = 109 g/mol. With this in mind:

I hope it helps!
Answer:
Yes , 5 mole of Iron Oxide has mass of 798.5 g
Explanation:
Formula of iron oxide:

Atomic mass of Fe = 55.84 amu
Atomic mass of O = 15.99 amu
Molar mass of Fe2O3 = 2(atomic mass of Fe) + 3(atomic mass of O)
= 2(55.84) + 3(15.99)
=111.68 + 47.97
= 159.69 g/mol
<u>Molar mass</u> always equal to <u>1 mole</u> of the substance.
1 mole = 159.69 g
5 mole =

= 798.45 g