Answer:
The compound contains lauryl sulfate and ammoium ions. Lauryl sulfate contains lauric acid (in black and white) , the fatty acid formed by the covalent bonds between C-C attached to hydrogens, and sulfate ions attached to lauric acid (in red) with C-S covalent bond. Sulfer is attached to oxygen by covalent bonds. In Ammonium ions, N is surrounded by four hydrogen atoms.
The question is incomplete, here is the complete question:
Calculate the initial rate for the formation of C at 25°C, if [A]=0.50 M and [B]=0.075 M. Express your answer to two significant figures and include the appropriate units.Consider the reaction
A + 2B ⇔ C
whose rate at 25°C was measured using three different sets of initial concentrations as listed in the following table:
The table is attached below as an image.
<u>Answer:</u> The initial rate for the formation of C at 25°C is
<u>Explanation:</u>
Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.
For the given chemical equation:
Rate law expression for the reaction:
where,
a = order with respect to A
b = order with respect to B
....(1)
....(2)
....(3)
Dividing 2 by 1, we get:
Dividing 3 by 1, we get:
Thus, the rate law becomes:
......(4)
Now, calculating the value of 'k' by using any expression.
Putting values in equation 1, we get:
Calculating the initial rate of formation of C by using equation 4, we get:
[A] = 0.50 M
[B] = 0.075 M
Putting values in equation 4, we get:
Hence, the initial rate for the formation of C at 25°C is
