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Chemistry

1 answer:

Semenov [28]2 years ago

7 0

C, 0.746 mol Ag.

1 mol Ag = 6.022 x 1023 atoms of Ag -> 4.49 x 1023 atoms of Ag x 1mol Ag/6.022 x 1023 atoms -> 0.746 mol Ag

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