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Mazyrski [523]
2 years ago
14

What is the percent yield of carbon dioxide of 2.5 mole of oxygen react and 32.4 g of carbon dioxide are produced?

Chemistry
1 answer:
Ugo [173]2 years ago
6 0

Answer:

86

Explanation:

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Equivalent massof sodium​
andre [41]

Answer:

Sodium

Formula : Na

Equivalent mass:23.0

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8 0
2 years ago
Please help question is in photo will give brainiest
IRISSAK [1]

Answer:

D

Explanation:

8 0
3 years ago
If 12.5 grams of strontium hydroxide is reacted with 150 mL of 3.5 M carbonic acid, identify the limiting reactant.
vesna_86 [32]

Answer:

Sr(OH)2

Explanation:

We'll begin by calculating the number of mole of carbonic acid in 150mL of 3.5 M carbonic acid solution. This is illustrated below:

Molarity = 3.5M

Volume = 150mL = 150/1000 = 0.15L

Mole of carbonic acid, H2CO3 =..?

Mole = Molarity x Volume

Mole of carbonic acid, H2CO3 = 3.5 x 0.15 = 0.525 mole.

Next, we shall convert 0.525 mole of carbonic acid, H2CO3 to grams.

Mole of H2CO3 = 0.525 mole

Molar mass of H2CO3 = (2x1) + 12 + (16x3) = 62g/mol.

Mass of H2CO3 =..?

Mass = mole x molar mass

Mass of H2CO3 = 0.525 x 62 = 32.55g

Next, we shall write the balanced equation for the reaction. This is given below:

Sr(OH)2 + H2CO3 → SrCO3 + 2H2O

Next, we shall determine the mass of Sr(OH)2 and H2CO3 that reacted from the balanced equation. This is illustrated below:

Molar mass of Sr(OH)2 = 88 + 2(16 + 1) = 88 + 2(17) = 122g/mol

Mass of Sr(OH)2 from the balanced equation = 1 x 122 = 122g

Molar mass of H2CO3 = (2x1) + 12 + (16x3) = 62g/mol.

Mass of H2CO3 from the balanced equation = 1 x 62 = 62g.

From the balanced equation above, 122g of Sr(OH)2 reacted with 62g of H2CO3.

Finally, we shall determine the limiting reactant as follow:

From the balanced equation above, 122g of Sr(OH)2 reacted with 62g of H2CO3.

Therefore, 12.5g of Sr(OH)2 will react with = (12.5 x 62)/122 = 6.35g.

We can see evidently from the calculations made above that it will take 6.35g out 32.55g of H2CO3 to react with 12.5g of Sr(OH)2. Therefore, Sr(OH)2 is the limiting reactant and H2CO3 is the excess reactant

5 0
3 years ago
Read 2 more answers
A hydrogen halide diffuses 1.49 times faster than HBr. This hydrogen halide is
marysya [2.9K]

To solve this problem, we must assume ideal gas behaviour so that we can use Graham’s law:

vA / vB = sqrt (MW_B / MW_A)

where,

<span>vA = speed of diffusion of A  (HBR)</span>

vB = speed of diffusion of B (unknown)

MW_B = molecular weight of B (unkown)

MW_A = molar weight of HBr = 80.91 amu

 

We know from the given that:

vA / vB = 1 / 1.49

 

So,

1/1.49 = sqrt (MW_B / 80.91)

MW_B = 36.44 g/mol

 

Since this unknown is also hydrogen halide, therefore this must be in the form of HX.

HX = 36.44 g/mol , therefore:

x = 35.44 g/mol

 

From the Periodic Table, Chlorine (Cl) has a molar mass of 35.44 g/mol. Therefore the hydrogen halide is:

HCl

6 0
3 years ago
What type(s) of bonding would be expected for each of the following materials: brass (a copper-zinc alloy), rubber, barium sulfi
mr_godi [17]

The force of attraction that results in holding of atoms or ions together in a molecule or crystal is said be bonding.  Bond formation can take place by either attraction or transfer of electrons. There are single, double, and triple bonds.  There are many types of bonding namely:

Covalent (sharing of electrons takes place).

Ionic (transfer of electrons takes place).

Metallic (ionized atoms of metals and the sea of electrons around them).

  • Brass (a copper-zinc alloy)

Brass is an alloy of metal that is copper and zinc. Hence, the metallic bonding is present in the brass.

  • Rubber

It is a polymer whose monomer unit is isoprene, which is a covalent compound. The isoprene units are attached in repeated units to form rubber by covalent bonding.

  • Barium sulfide (BaS)

Due to the large electronegativity difference between barium and sulfur, barium sulfide is an ionic compound. Thus, ionic bonding is present in barium sulfide.

  • Solid xenon

Only xenon atoms are present in solid xenon which are interacted by weak Van der Waal's interactions.

  • Bronze

Bronze is an alloy of metal that is copper and tin. Hence, the metallic bonding is present in the brass.

  • Nylon

It is a polymer whose monomer unit is caprolactam, which is a covalent compound. The caprolactam units are attached in repeated units to form nylon by covalent bonding.

  • Aluminum phosphide (AlP)

Aluminum phosphide is a covalent compound and thus involves covalent bonding.

7 0
3 years ago
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