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Marysya12 [62]
1 year ago
5

select from this list the one metal or alloy that is best suited for each of the following applications, and cite at least one r

eason for your choice:
Chemistry
1 answer:
Brut [27]1 year ago
3 0

<em>List of metal or alloy that is best-suited include :</em>

<em>1) Block of an </em><em>internal combustion </em><em>engine is made of grey cast </em><em>iron </em><em>because it is </em><em>ductile </em><em>and hard enough to bear the loads.</em>

<em>2) Steam heat exchanger is made up of </em><em>stainless steel </em><em>material as it has high resistance to </em><em>corrosion </em><em>and has the capacity to bear high-</em><em>temperature </em><em>differences.</em>

<em>3) For jet engine </em><em>turbofan blades</em><em>, titanium alloys are being used because they can able to bear high pressure and high energy loads.</em>

<em>4) Tool </em><em>steel </em><em>is used to make drill bit material as it has high </em><em>tensile </em><em>and point strength.</em>

<em>5) </em><em>Aluminum alloys </em><em>are used for </em><em>cryogenic </em><em>applications as it is the best suited for work at low </em><em>temperatures</em><em>.</em>

<em>6) </em><em>Magnesium </em><em>is used for </em><em>pyrotechnics </em><em>as it gives works on the effect of heat, </em><em>light</em><em>, and gas. </em>

<em />

<em />

Alloy, a metallic substance composed of two or more elements, as both a compound or a solution. The components of alloys are ordinarily themselves metals, though carbon, a nonmetal, is an essential constituent of metal.

Alloys, in trendy, are more potent and harder, less malleable, much less ductile, and greater corrosion-resistant than the alloy's predominant metallic.

An alloy is created with the aid of mixing metallic with another issue, both any other metal or a nonmetal substance. Metallic alloys are commonly made by means of melting the substances, mixing them collectively, after which letting them cool to room temperature, ensuing in a strong material.

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Learn more about Alloy here:-brainly.com/question/1759694

#SPJ4

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What size volumetric flask would you use to create a 1.00M solution using 166.00 g of KI?
mr Goodwill [35]

Answer:

A 1 liter volumetric flask should be used.

Explanation:

First we <u>convert 166.00 g of KI into moles</u>, using its <em>molar mass</em>:

Molar mass of KI = Molar mass of K + Molar mass of I = 166 g/mol

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Then we <u>calculate the required volume</u>, using the <em>definition of molarity</em>:

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Liters = moles / molarity

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2 years ago
Why are most organic compounds nonconducting and insoluble in water?
maksim [4K]
I think the correct answers from the choices listed above are the second and the last options. Organic compounds are nonducting and insoluble in water because of the bonds that these compounds contain. Most organic compounds don't dissolve in water because they are nonpolar. They don't conduct electricity because they are covalent, not ionic.
4 0
3 years ago
Read 2 more answers
an engineer wishes to design a container that will hold 12.0 mol of ethane at a pressure no greater than 5.00x10*2 kPa and a tem
OleMash [197]

Answer:

The minimum volume of the container is 0.0649 cubic meters, which is the same as 64.9 liters.

Explanation:

Assume that ethane behaves as an ideal gas under these conditions.

By the ideal gas law,

P\cdot V = n\cdot R\cdot T,

\displaystyle V = \frac{n\cdot R\cdot T}{P}.

where

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  • V is the volume of the gas,
  • n is the number of moles of particles in this gas,
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  • T is the absolute temperature of the gas (in degrees Kelvins.)

The numerical value of R will be 8.314 if P, V, and T are in SI units. Convert these values to SI units:

  • P =\rm 5.00\times 10^{2}\;kPa = 5.00\times 10^{2}\times 10^{3}\; Pa = 5.00\times 10^{5}\; Pa;
  • V shall be in cubic meters, \rm m^{3};
  • T = \rm 52.0 \textdegree C = (52.0 + 273.15)\; K = 325.15\; K.

Apply the ideal gas law:

\displaystyle \begin{aligned}V &= \frac{n\cdot R\cdot T}{P}\\ &= \frac{12.0\times 8.314\times 325.15}{5.00\times 10^{5}}\\ &= \rm 0.0649\; m^{3} \\ &= \rm (0.0649\times 10^{3})\; L \\ &=\rm 64.9\; L\end{aligned}.

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