Answer:
0.45 grams of hydrogen and 3.53 grams of oxygen will be formed, when 4.05 grams of water is used.
Explanation:
The given reaction is
2 moles of is used to form 2 moles of and 1 mole of
As 1 mole of , 1 mole of , and 1 mole of .
So, 36 grams of is used to form 4 grams of and 32 grams of
Therefore, 1 gram of is used to form 4/36 grams of and 32/36 grams of
Therefore, 4.05 gram of is used to form (1/9)4.09=0.45 grams of and (8/9)4.05=3.53 grams of .
Hence, 0.45 grams of hydrogen and 3.53 grams of oxygen will be formed, when 4.05 grams of water is used.
Answer: lava, crater
Answer: Option A
Explanation: 2 Na + Cl2---> 2NaCl
Here Oxidation no of Na is zero while in NaCl is +1. That means oxidation state of Na increased from 0 to +1 hence oxidation
While Cl2 has zero in molecular form and -1 in NaCl hence Reduction (Oxidation no decreased from zero to -1)
Halogens(cl) always shows -1 oxidation state and IA group elements(Na)shows +1 oxidation state
Answer: 0.18 M
Initial molarity, M1 = 0.8 M
Initial olume, V1 = 225 ml
Final volume, V2 = 1000 ml
Final Molarity, M2 = M1V1/V2
= 0.8 x 225/1000
= 0.18 M