Answer:
The answer is 3
C2H5OH + O2 CO2 +H2O (unbalanced)
C2H5OH +3O2(g). 2CO2(g)+3H2O(balanced)
Answer:
The suitable equation for this reaction is
2CO + O₂ -----> 2CO₂
Here, we are given that we have 2 grams of O₂
From the equation, we can see that 2 * Moles of O₂ = Moles of CO₂
Moles of O₂:
2/32 = 1/16 moles
Therefore, the number of moles of CO₂ is twice the moles of O₂
Moles of CO₂ = 2 * 1/16
Moles of CO₂ formed = 1/8 moles
Mass of CO₂ formed = Molar mass of CO₂ * Moles of CO₂
Mass of CO₂ formed = 44 * 1/8
Mass of CO₂ formed = 5.5 grams
Hence, option B is correct
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the second one, any change in a DNA gene or chromosome
The 8 hour shift is from 7.00 am to 3.00 pm.<span>
<span>At the beginning, from 7.00 am to 9.30am (2.5 hrs.),<span> the client has normal saline which </span></span>is
infusing at 125 ml/hr.
Hence amount of normal saline which was injected= 2.5 hrs. x 125 ml/hr.
= 312.5 ml
from 9.30am to 3.00 pm (5.5 hrs) lactated ringer solution, which is to infuse at 100 ml/hr was
given.
Hence amount of lactated ringer solution given = 5.5 hrs x 100 ml/hr
= 550 ml
Total amount of IV solution given = normal saline
+ lactated ringer solution
= 312.5 ml + 550
ml
= 862.5 ml
<span>
= 863 ml</span></span>
Answer:
See explanation
Explanation:
Since the -CH3CN and the -F are in 1,4 position, then the synthesis started with flourobenzene. This has to be because -F is ortho-para directing in nucleophilic substitution.
The next step is the Friedel craft alkylation of the substrate. The alkyl group is directed to the para position by the -F.
Bromination using NBS yields an alkyl bromide that undergoes SN2 substitution to yield the target compound.
