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Darya [45]
3 years ago
11

Which of the following is a reasonable ground-state electron configuration?

Chemistry
1 answer:
sergeinik [125]3 years ago
6 0
<span>1s^22s^22p^63s^1 i think</span>
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Help, 8th grade Science
valentinak56 [21]

Answer:

Control container

Explanation:

5 0
3 years ago
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Glucozo công thức phân tử
olganol [36]

Answer:I would copy and past but that’s a lot of work just read it

Explanation:

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3 years ago
Slicing an average loaf of bread gives 13 medium thickness slices. Each slice of bread is to be coated with 0.0500 oz of mayonna
AlexFokin [52]

Answer:

36 loaves of bread and 18.48 ounces of mayonnaise are needed to make all of the sandwiches.

Explanation:

Number of slices of ham = 231

Given that each sandwich has 1 slice of ham.

Then 231 slices of ham will be in :

1\times 231 =231 sandwiches

A single sandwich is made up of 2 bread slices , Then bread slices in 231 sandwiches will be :

231\times 2=462

Each bread slice is applied with 0.0500 ounce of mayonnaise.

Then 462 bread slices will have :

462\times 0.0500 ounces=18.48 Oz

1 bread loaf = 13 bread slices

Then breads loves in 462  bread slices :

\frac{462}{13}=35.54\approx 36

36 loaves of bread and 18.48 ounces of mayonnaise are needed to make all of the sandwiches.

8 0
4 years ago
Which compound is ionic?<br> 1. CaBr2 <br> 2. NO2<br> 3. CH4<br> 4. NBr3
NARA [144]
It is number 1. CaBr2
3 0
3 years ago
A chemist adds 1.80L of a 1.1/molL aluminum chloride AlCl3 solution to a reaction flask. Calculate the millimoles of aluminum ch
amm1812

Answer:

2000 millimoles of AlCl₃

Explanation:

From the question given above, the following data were obtained:

Volume of solution = 1.8 L

Molarity of solution = 1.1 mol /L

Millmole of AlCl₃ =?

Next, we shall determine the number of mole of AlCl₃ in the solution.

This can be obtained as follow:

Volume of solution = 1.8 L

Molarity of AlCl₃ solution = 1.1 mol /L

Number of mole of AlCl₃ =?

Molarity = mole /Volume

1.1 = Number of mole of AlCl₃ / 1.8

Cross multiply

Number of mole of AlCl₃ = 1.1 × 1.8

Number of mole of AlCl₃ = 1.98 moles

Finally, we shall convert 1.98 moles to millimoles. This can be obtained as follow:

1 mole = 1000 millimoles

Therefore,

1.98 mole = 1.98 mole × 1000 millimoles / 1 mole

1.98 mole = 1980 millimoles

1.98 mole ≈ 2000 millimoles

Thus, the chemist added 2000 millimoles of AlCl₃

7 0
3 years ago
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