Question

What is the value of V^1?

Answer 1

$\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}$

Actually Welcome to the Concept of the Current Electricity.

Since here, A potential divider is setup with two resisters in series, that is 3 ohm and 6 ohm.

As the voltage is always in directly proportional to the resistance,by ohm law,

V = IR, so the increase in Voltage will lead to increase in the resistance too.

hence,

for 6 ohm the voltage is 4 V, then for the 3 ohm it would be ,

V1 = (4/6)*3

==> V1 = 2 Volts,

==> hence the potential V1 = 2V