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Darina [25.2K]
3 years ago
13

The reaction of 2-methylbutane with chlorine would yield how many monochloro derivatives (include stereoisomers)?

Chemistry
2 answers:
zimovet [89]3 years ago
7 0
The reaction  of  2  methylbutane  with   chlorine  yield  5 monochloro  derivative.   Methylbutane  has  four  carbon  atoms  which  react with   chlorine.  The  carbon  with antibonding  will  be  chiral   and  it  will react  with  chlorine. there  will  be  four  difference  group  around  chiral  carbon  hence  it  will  have  stereoisomers.
Effectus [21]3 years ago
3 0

The reaction of 2 methyl butane with chlorine would yield 5 mono chloro derivatives.

Explanation

The organic compound of 2 methyl butane will have 5 C-H groups.

As butane means 4 CH group and one methyl at 2nd position means one more CH group, so totally 5 CH group is present.

These 5 CH group can react with chlorine and form 5 mono chloro derivatives like CH3Cl, CH2Cl etc.

The chirality present in the anti-bonded carbon atoms leads to the exhibition of stereoisomerism while forming mono chloro derivatives.

Thus, it can be confirmed that 5 mono chloro derivatives will be produced when 2 methyl butane reacts with chlorine.

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Answer:

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Explanation:

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Toluene (C6H5CH3 ), an organic compound often used as a solvent in paints, is mixed with a similar organic compound, benzene (C6
Sergeeva-Olga [200]

Explanation:

The given data is as follows.

 Weight of solute = 75.8 g,   Molecular weight of solute (toulene) = 92.13 g/mol,    volume = 200 ml

  • Therefore, molarity of toulene is calculated as follows.

      Molarity = \frac{\text{weight of solute}}{\text{molecular weight of solute}} \times \frac{1000}{\text{volume of solution in ml}}

                    = \frac{75.8 g}{92.13 g/mol} \times \frac{1000}{200 ml}

                    = 4.11 M

Hence, molarity of toulene is 4.11 M.

  • As molality is the number of moles of solute present in kg of solvent.

So, we will calculate the molality of toulene as follows.

   Molality = \frac{\text{given weight of solute}}{\text{given molecular weight of solute}} \times \frac{1000}{\text{weight of solvent in grams}}

             = \frac{75.8 g}{92.13 g/mol} \times \frac{1000}{95.6 g}

             = 8.6 m

Hence, molality of given toulene solution is 8.6 m.

  • Now, calculate the number of moles of toulene as follows.

       No. of moles = \frac{mass}{\text{molar mass}}

                             = \frac{75.8 g}{92.13 g/mol}

                             = 0.8227 mol

Now, no. of moles of benzene will be as follows.

     No. of moles = \frac{mass}{\text{molar mass}}

                             = \frac{95.6 g}{78.11 g/mol}

                             = 1.2239 mol

Hence, the mole fraction of toulene is as follows.

         Mole fraction = \frac{\text{moles of toulene}}{\text{total moles}}

                             = \frac{0.8227 mol}{(0.8227 + 1.2239) mol}

                             = 0.402

Hence, mole fraction of toulene is 0.402.

  • As density of given solution is 0.857 g/cm^{3} so, we will calculate the mass of solution as follows.

         Density = \frac{mass}{volume}

     0.857 g/cm^{3} = \frac{mass}{200 ml}      (As 1 cm^{3} = 1 g)

                      mass = 171.4 g

Therefore, calculate the mass percent of toulene as follows.

      Mass % = \frac{\text{mass of solute}}{\text{mass of solution}} \times 100

                   = \frac{75.8 g}{171.4 g} \times 100

                   = 44.22%

Therefore, mass percent of toulene is 44.22%.

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BigorU [14]
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Answer:

5

Explanation:

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Now, on the right hand side, we can see we only have two hydrogen atoms in the water molecule. Now, to make equal the number of hydrogen atoms on both sides, we simply multiply the number of hydrogen there by 5 to make it 10 too

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