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3 years ago

The reaction of 2-methylbutane with chlorine would yield how many monochloro derivatives (include stereoisomers)?

2 answers:

7 0

The reaction of 2 methylbutane with chlorine yield 5 monochloro derivative. Methylbutane has four carbon atoms which react with chlorine. The carbon with antibonding will be chiral and it will react with chlorine. there will be four difference group around chiral carbon hence it will have stereoisomers.

Effectus [21]3 years ago

3 0

The reaction of 2 methyl butane with chlorine would yield 5 mono chloro derivatives.

Explanation

The organic compound of 2 methyl butane will have 5 C-H groups.

As butane means 4 CH group and one methyl at 2nd position means one more CH group, so totally 5 CH group is present.

These 5 CH group can react with chlorine and form 5 mono chloro derivatives like CH3Cl, CH2Cl etc.

The chirality present in the anti-bonded carbon atoms leads to the exhibition of stereoisomerism while forming mono chloro derivatives.

Thus, it can be confirmed that 5 mono chloro derivatives will be produced when 2 methyl butane reacts with chlorine.

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Convert 5° C into Fahrenheit.

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Answer:

5 in celcius is 41 in fahrenheit!

Explanation:

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Toluene (C6H5CH3 ), an organic compound often used as a solvent in paints, is mixed with a similar organic compound, benzene (C6

Sergeeva-Olga [200]

Explanation:

The given data is as follows.

Weight of solute = 75.8 g, Molecular weight of solute (toulene) = 92.13 g/mol, volume = 200 ml

Therefore, molarity of toulene is calculated as follows.

Molarity = $\frac{\text{weight of solute}}{\text{molecular weight of solute}} \times \frac{1000}{\text{volume of solution in ml}}$

= $\frac{75.8 g}{92.13 g/mol} \times \frac{1000}{200 ml}$

= 4.11 M

Hence, molarity of toulene is 4.11 M.

As molality is the number of moles of solute present in kg of solvent.

So, we will calculate the molality of toulene as follows.

Molality = $\frac{\text{given weight of solute}}{\text{given molecular weight of solute}} \times \frac{1000}{\text{weight of solvent in grams}}$

= $\frac{75.8 g}{92.13 g/mol} \times \frac{1000}{95.6 g}$

= 8.6 m

Hence, molality of given toulene solution is 8.6 m.

Now, calculate the number of moles of toulene as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

= $\frac{75.8 g}{92.13 g/mol}$

= 0.8227 mol

Now, no. of moles of benzene will be as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

= $\frac{95.6 g}{78.11 g/mol}$

= 1.2239 mol

Hence, the mole fraction of toulene is as follows.

Mole fraction = $\frac{\text{moles of toulene}}{\text{total moles}}$

= $\frac{0.8227 mol}{(0.8227 + 1.2239) mol}$

= 0.402

Hence, mole fraction of toulene is 0.402.

As density of given solution is 0.857 $g/cm^{3}$ so, we will calculate the mass of solution as follows.

Density = $\frac{mass}{volume}$

0.857 $g/cm^{3}$ = $\frac{mass}{200 ml}$ (As 1 $cm^{3}$ = 1 g)

mass = 171.4 g

Therefore, calculate the mass percent of toulene as follows.

Mass % = $\frac{\text{mass of solute}}{\text{mass of solution}} \times 100$

= $\frac{75.8 g}{171.4 g} \times 100$

= 44.22%

Therefore, mass percent of toulene is 44.22%.

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The answer you’re looking for is 0.250

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