The answer is 509 m.
Let point B be 253 m from point A. Let point C be 64 s away from point B.
Let d1 be the displacements from point A to point B and d2 and be the displacements from point B to point C
Step 1. Calculate the displacement from the point B after 64 s.
Step 2. Calculate the displacement from the point A by summing up two distances (d1 and d2).
Step 1.
v = d2/t
v = 4 m/s
d2 = ?
t = 64s
____
4 = d2/64
d2 = 64 * 4 = 256 m
Step 2:
d = d1 + d2
d1 = 253 m
d2 = 256 m
d = 253 + 256 = 509m
Answer:
3.06 m
Explanation:
The work done by the man against the gravity is given by
Where F is the force i.e. weight of the man and h is the displacement and 
is the angle between displacement and force
Since F=mg and is zero
W = mgh
Also, Work=power* time
Therefore, Power*time=mgh
Substituting power for 120 W, time for 20 seconds, g as 9.81 m/s2 and m as 80 Kg
120*20=80*9.81*h and making he the subject of the formula
Therefore, the height is approximately 3.06 m
the rope wouldnt move, the force of both dogs pulling us also called tension
Given :
Mass =5kg
T
1
=20
∘
C,T
2
=100
∘
C
ΔT=100−20=80
∘
C
Q=m×C×ΔT
where C= specific heat capacity of water
=4200J/(kgK)
Q=5×4200×80
=1680000 Joule.
=1680KJ
Answer:
L=N/I*magnetic flux
=N/I*BA=N*mu(0)NIA/2pi*R=mu(0)N^2/2pi*R)*Pi*a^2
=mu(0)N^2a^2/2R
Explanation:
