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Klio2033 [76]
3 years ago
5

In Hans Oersted’s experiment, why did a compass needle move when an electric current flowed through a nearby wire?

Physics
2 answers:
Zinaida [17]3 years ago
6 0

Answer:

The answer should be: D

Explanation: The magenetic field Would not move a place without a magnetic field.

Rashid [163]3 years ago
5 0
D. The current changed earths magnetic field
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Which of the following examples does not illustrate Newton's first law of motion?
Stella [2.4K]

Answer: B

Explanation: The rocket is accelerating the the spacecraft. Accelerating  relates to Newtons Second Law of Motion.

6 0
3 years ago
The mass of a regulation tennis ball is 57 g. The ball is in contact with the tennis racket for 30 ms. The ball was served at 73
yaroslaw [1]

Answer:

Correct answer:  F₂ = 104.5 N

Explanation:

Given:

m = 57 g = 57 · 10⁻³ kg

Δt = 30 ms = 30 · 10 ⁻³ seconds

V₁ = 73.14 m/s   service speed

V₂ = 55 m/s  returned speed

M = m · V  Momentum or Impulse

You forgot to indicate what time the ball contact when returning.

We will assume that the time is the same Δt = 30 ms = 30 10 ⁻³ seconds.

The formula for calculating force is according to Newton's second law is:

F = ΔM / Δt = m · ΔV / Δt

Force during service is:

F₁ = 57 · 10⁻³ · 73.14 / 30 · 10 ⁻³ = 138.97 N

F₁ = 138.97 N

Returned force:

F₂ =  57 · 10⁻³ · 55 / 30 · 10 ⁻³ = 104.5 N

F₂ =  104.5 N

God is with you!!!

8 0
4 years ago
(a) Write an equation describing a sinusoidal transverse wave traveling on a cord in the positive of a y axis with an angular wa
Vedmedyk [2.9K]

Missing data: the wave number

k=60 cm^{-1}

(a)  z = 0.003 sin (6000y-31.4 t)

For a transverse wave travelling in the positive y-direction and with vibration along the z-direction, the equation of the wave is

z = A sin (ky-\omega t)

where

A is the amplitude of the wave

k is the wave number

\omega is the angular frequency

t is the time

In this situation:

A = 3.0 mm = 0.003 m is the amplitude

k = 60 cm^{-1} = 6000 m^{-1} is the wave number

T = 0.20 s is the period, so the angular frequency is

\omega=\frac{2\pi}{T}=\frac{2\pi}{0.20}=31.4 rad/s

So, the wave equation (in meters) is

z = 0.003 sin (6000y-31.4 t)

(b) 0.094 m/s

For a transverse wave, the transverse speed is equal to the derivative of the displacement of the wave, so in this case:

v_t = z' = -A \omega cos (ky-\omega t)

So the maximum transverse wave occurs when the cosine term is equal to 1, therefore the maximum transverse speed must be

v_{t}_{max} =\omega A

where

\omega = 31.4 rad/s\\A = 0.003 m

Substituting,

v_{t}_{max}=(31.4)(0.003)=0.094 m/s

(c) 5.24 mm/s

The wave speed is given by

v=f \lambda

where

f is the frequency of the wave

\lambda is the wavelength

The frequency can be found from the angular frequency:

f=\frac{\omega}{2\pi}=\frac{31.4}{2\pi}=5 Hz

While the wavelength can be found from the wave number:

\lambda = \frac{2\pi}{k}=\frac{2\pi}{6000}=1.05\cdot 10^{-3} m

Therefore, the wave speed is

v=(5)(1.05\cdot 10^{-3} )=5.24 \cdot 10^{-3} m/s = 5.24 mm/s

7 0
4 years ago
Because she had serious traffic accident on Friday the 13th of last month, Felicia is conceived that all Friday the 13th will br
elena-s [515]

Answer:

Illusory correlation

Explanation:

Illusory correlation is a psychological phenomenon of sensing a correlation or relationship between a particular quantity and other variables however unrelated the two variables may be. A person may establish such connections, which are indeed false connections, as a result of over emphasis on novel incidents that are easily noticed due to them being salient

For example, when a waiter at a restaurant is being rude to a person after the person was made to walk under a ladder due to ongoing construction.

4 0
3 years ago
The position of a particle is given by ~r(t) = (3.0 t2 ˆi + 5.0 ˆj j 6.0 t kˆ) m
Julli [10]

Answer:

v=(6ti+6k)\ m/s

Explanation:

Given that,

The position of a particle is given by :

r(t) = (3.0 t^2 i + 5.0j+ 6.0 tk) m

Let us assume we need to find its velocity.

We know that,

v=\dfrac{dr}{dt}\\\\=\dfrac{d}{dt}(3.0 t^2 i + 5.0j+ 6.0 tk) \\\\=(6ti+6k)\ m/s

So, the velocity of the particle is (6ti+6k)\ m/s.

5 0
3 years ago
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