Hydrocarbons that lack π bond are called saturated hydrocarbons or alkanes
<h3>Hydrocarbons</h3>
- Hydrocarbon is an organic compound consisting of hydrogen and carbon.
- Hydrocarbons is an examples of 14 group hydrides.
- Hydrocarbons are colorless and hydrophobic.
- Their odors are usually like gasoline or lighter fluid.
- In oil and gas industry, the hydrocarbon in term, combines petroleum and natural gas they are the two naturally occurring phases of hydrocarbon.
<h3>Alkanes</h3>
- Alkanes also konwn as parafins
- They are called as saturated hydrocarbons
- Alkanes contain hydrogen and carbons arranged in tree structure
- Alkanes have two main sources petroleum and natural gas.
Therefore, Hydrocarbons that lack π bond are called saturated hydrocarbons
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The balanced chemical reaction is expressed as:
M + F2 = MF2
To determine the moles of the element fluorine present in the product, we need to determine the moles of the product formed from the reaction and relate this value to the ratio of the elements in MF2. We do as follows:
moles MF2 produced = 0.600 mol M ( 1 mol MF2 / 1 mol M ) = 0.600 mol MF2
molar mass MF2 = 46.8 g MF2 / 0.6 mol MF2 = 78 g/mol
moles MF2 = 46.8 g ( 1 mol / 78 g ) = 0.6 mol
moles F = 0.6 mol MF2 ( 2 mol F / 1 mol MF2 ) = 1.2 moles F
First, you will have to write out and balance the equation, so:
Because we’re looking at a single element reacting with an acid, we know that the reaction must be a single replacement.
Mg + HCl —-> MgCl2 + H2
We use H2, because hydrogen can only exist by itself when covalently bonded to itself, in a diatomic state.
Mg has an oxidation state of +2, while Cl has an oxidation state of -1. Therefore, you need 2 Cl to cancel the charge fully.
Now it needs to be balanced, so you get:
Mg + 2HCl —-> MgCl2 + H2
Now we have molar ratios to do our conversions
So we’ll use stoichiometry to find the theoretical yield for both reactants, and whichever one is the LEAST is the answer.
(32.5g Mg) (1mol/24.3g) (1mol MgCl2/1 mol Mg) (95.3g/1 mol MgCl2) = 127.5g
(32.5g HCl) (1mol/36.5) (1mol MgCl2/2mol HCl) (95.3g/1 mol MgCl2) = 42.4g
So, you will get 42.4 g of MgCl2
Answer:
1) high pH is required
2) other ions are precipitated along with the strontium ions
Explanation:
According to the solubility rules all phosphates are insoluble except those of sodium, potassium, and ammonium. This implies that strontium phosphate is insoluble in water. This explains why strontium ions can be precipitated from drinking water supply using phosphate. The main problem with the precipitation of strontium using phosphate is that it usually requires a high pH as the precipitation occurs under very alkaline conditions.
The main reason why the results may not be accurate is that other ions are precipitated along with the strontium such as calcium ions and magnesium ions. This may lead to inaccurate determination of the amount of strontium ions present.
Answer:
The correct option is;
The electronegativity increases
Explanation:
The electronegativity is the measure of an atom's ability to attract a shared electron pair. The electronegativity of an atom is dependent on the atom's atomic number and the separation distance between the electrons in the valence shell and the positively charged nucleus such that an increase in the atomic number results in an increase in electronegativity and an increase in the distance between the valence electrons and the nucleus, leads to a decrease in electronegativity.
