Using the slope-intercept form, the slope is 3 3 . To find an equation that is parallel<span>to </span>y=3x−2 y<span> = 3 x - </span>2<span> , the slopes must be equal. Using the slope of the equation, find the </span>parallel line<span> using the point-slope formula. Find the value of b b using the formula for the equation of a </span>line<span>.</span>
Answer: 200ft
Step-by-step explanation:
43+43+57+57=200
Step-by-step explanation:
I assume that "ground" is at 0 ft height. which is in an actual scenario not airways the case.
y = -16x² + 64x + 89
shows us that the tower is 89 ft tall (the result for x = 0, at the start).
anyway, if the original assumption is correct, then we need to solve
0 = -16x² + 64x + 89
the general solution for such a quadratic equation is
x = (-b ± sqrt(b² - 4ac))/)2a)
in our case
a = -16
b = 64
c = 89
x = (-64 ± sqrt(64² - 4×-16×89))/(2×-16) =
= (-64 ± sqrt(4096 + 5696))/-32 =
= (-64 ± sqrt(9792))/-32
x1 = (-64 + 98.95453501...)/-32 = -1.092329219... s
x2 = (-64 - 98.95453501...)/-32 = 5.092329219... s
the negative solution for time is but useful here (it would be the time calculated back to ground at the start).
so, x2 is our solution.
the rocket hits the ground after about 5.09 seconds.
The equation in y = mx+b form is y = -450x+2745
where,
x = number of hours that have passed by
y = distance to destination in miles
The y intercept is 2745 since this is the initial starting y value, aka the starting distance. Therefore b = 2745.
The slope is -450 or -450/1 since for each hour, the distance goes down by 450. You can think of it as
slope = (change in y)/(change in x)
slope = (change in distance)/(change in time)
slope = (-450 miles)/(1 hour)
slope = -450
