Chanasia buys a plastic bucket. The bucket weighs 460 g. The label on the bucket says made with 20% recycled plastic. How many g
1 answer:
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a_15 = 90
a_n = 6n
Step-by-step explanation:
Given sequence is:
6, 12, 18, 24,...
First of all we have to find the common difference. The common difference is the difference between consecutive terms of an arithmetic sequence.
Here,
The general form for arithmetic sequence is:
Putting the values for a_1 and d
<u>a) Find a15</u>
<u>b) Write an equation for the nth term.</u>
The equation is: a_n=6n
Keywords: Arithmetic sequence, Common Difference
Learn more about arithmetic sequence at:
#LearnwithBrainly
Answer:
We conclude that the percentage of blue candies is equal to 29%.
Step-by-step explanation:
We are given that in a random selection of 100 colored candies, 28% of them are blue. The candy company claims that the percentage of blue candies is equal to 29%.
Let p = <u><em>population percentage of blue candies</em></u>
So, Null Hypothesis, : p = 29% {means that the percentage of blue candies is equal to 29%}
Alternate Hypothesis, : p
29% {means that the percentage of blue candies is different from 29%}
The test statistics that will be used here is <u>One-sample z-test for</u> <u>proportions</u>;
T.S. = ~ N(0,1)
where, = sample proportion of blue coloured candies = 28%
n = sample of colored candies = 100
So, <u><em>the test statistics</em></u> =
= -0.22
The value of the z-test statistics is -0.22.
<u>Also, the P-value of the test statistics is given by;</u>
P-value = P(Z < -0.22) = 1 - P(Z 0.22)
= 1 - 0.5871 = 0.4129
Now, at a 0.10 level of significance, the z table gives a critical value of -1.645 and 1.645 for the two-tailed test.
Since the value of our test statistics lies within the range of critical values of z, <u><em>so we insufficient evidence to reject our null hypothesis</em></u> as it will not fall in the rejection region.
Therefore, we conclude that the percentage of blue candies is equal to 29%.