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Sveta_85 [38]
3 years ago
8

In lab you reacted 60 grams of propane (C3H8) with 13 grams of oxygen gas (O2). Your

Chemistry
1 answer:
Andre45 [30]3 years ago
5 0

Answer:

120g

Explanation:

Based on the reaction, when 1 mole of propane and 5 moles of oxygen react, 3 moles of CO2 and 4 moles of H2O are produced. The ratio of production is 3 moles of CO2 per 4 moles of H2O.

Thus, we need to convert mass of water to moles using its molar mass:

Moles H2O (Molar mass: 18g/mol):

63g H2O * (1mol / 18g) = 3.5 moles H2O

Converting to moles of CO2:

3.5 moles H2O * (3 moles CO2 / 4 moles H2O) = 2.625 moles CO2

Mass CO2 (Molar mass: 44g/mol):

2.625 moles CO2 * (44g / mol) = 115.5g of CO2 are released

<h3>120g </h3>

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Which one of the following will change the value of an equilibrium constant?
Ad libitum [116K]

Answer:

(E) changing temperature

Explanation:

Consider the following reversible balanced reaction:

aA+bB⇋cC+dD

If we know the molar concentrations of each of the reaction species, we can find the value of Kc using the relationship:

Kc = ([C]^c * [D]^d) / ([A]^a * [B]^b)

where:

[C] and [D] are the concentrations of the products in the equilibrium; [A] and [B] reagent concentrations in equilibrium; already; b; c and d are the stoichiometric coefficients of the balanced equation. Concentrations are commonly expressed in molarity, which has units of moles / 1

There are some important things to remember when calculating Kc:

-  <em>Kc is a constant for a specific reaction at a specific temperature</em>. If you change the reaction temperature, then Kc also changes

- Pure solids and liquids, including solvents, are not considered for equilibrium expression.

- The reaction must be balanced with the written coefficients as the minimum possible integer value in order to obtain the correct value of Kc

8 0
3 years ago
Hunting lions has been banned in some parts of Africa. If this law is enforced, what can we expect to happen to the populations
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Be(OH)2 is solid why?​
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no it's not solid rather it's an aqueous

Explanation:

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8 0
2 years ago
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1. C

2. C

3. In elastic deformation, the deformed body returns to its original shape and size after the stresses are gone. In ductile deformation, there is a permanent change in the shape and size but no fracturing occurs. In brittle deformation, the body fractures after the strength is above the limit. 

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I hope this helped :D

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