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Oxana [17]
3 years ago
14

Which planet is known as evening star​

Physics
1 answer:
Verdich [7]3 years ago
8 0

Answer:

Mercury is a metal that is used in

Mercury can be seen as an evening "star" near the sun's setting point or as a morning "star" near the sun's rising point. The evening star was given the name Hermes, and the morning star was given the name Apollo, since the ancient Greeks thought they were two separate things. Mercury, the Roman god's messenger, is the planet's name.

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what is the wavelength of waves at the beach if they have a frequency of 0.3 Hz and they move at 7.1 m/s?
Reil [10]

Answer:

23.67 m

Explanation:

We are given;

Frequency; f = 0.3 Hz

Speed; v = 7.1 m/s

Now, formula to get the wavelength is from the wave equation which is;

v = fλ

Where λ is wavelength

Making λ the subject, we have;

λ = v/f

λ = 7.1/0.3

λ = 23.67 m

5 0
3 years ago
Which of the following best completes the sentence for Newton's Third Law? In every interaction,
nataly862011 [7]

Answer:

D in pairs

Explanation:

Forces always come in pairs - equal and opposite action-reaction force pairs.

3 0
3 years ago
Read 2 more answers
A spaceship travels toward the Earth at a speed of 0.97c. The occupants of the ship are standing with their torsos parallel to t
Ket [755]

Answer:

Explanation:

We shall apply length contraction einstein's relativistic formula to calculate the length observed by observer on the earth . For the observer , increased length will be observed for an observer on the earth

L=\frac{.5}{\sqrt{1-(\frac{.97c}{c})^2 } }

L=\frac{.5}{.24}

L= 2.05

The length will appear to be 2.05 m . and width will appear to be .5 m  to the observer on the spaceship. . It is so because it is length which is moving parallel to the direction of travel. Width will remain unchanged.  

3 0
4 years ago
Two objects are dropped from rest from the same height. Object A falls through a distance <img src="https://tex.z-dn.net/?f=d_A"
Alenkinab [10]

Answer:

The answer to your question is given below

Explanation:

Since both object A and B were dropped from the same height and the air resistance is negligible, both object A and B will get to the ground at the same time.

From the question, we were told that object A falls through a distance to dA at time t and object B falls through a distance of dB at time 2t.

Remember, both objects must get to the ground at the same time..!

Let the time taken for both objects to get to the ground be t.

Time A = Time B = t

But B falls through time 2t

Therefore,

Time A = Time B = 2t

Height = 1/2gt^2

For A:

Time = 2t

dA = 1/2 x g x (2t)^2

dA = 1/2g x 4t^2

For B

Time = t

dB = 1/2 x g x t^2

Equating dA and dB

dA = dB

1/2g x 4t^2 = 1/2 x g x t^2

Cancel out 1/2, g and t^2

4 = 1

4dA = dB

Divide both side by 4

dA = 1/4 dB

8 0
3 years ago
The power of the situation represents
lions [1.4K]

I think the answer is c but I'm not sure

3 0
3 years ago
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