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8090 [49]
3 years ago
12

What are other words for saying that a wave is "transmitted" through a medium?​

Physics
1 answer:
NNADVOKAT [17]3 years ago
4 0

Answer:

Other words for saying that a wave is transmitted through a medium would be a wave transfers from one medium into another.

Explanation:

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A light wave travels through water (n=1.33) at an angle of 35º. What angle
san4es73 [151]

Answer:

49.7^{\circ}

Explanation:

We can solve the problem by using Snell's law:

n_1 sin \theta_1 = n_2 sin \theta_2

where

n1 = 1.33 is the index of refraction of the first medium (water)

n2 = 1.00 is the index of refraction of the second medium (air)

\theta_1 = 35^{\circ} is the angle of incidence of the wave in water

\theta_2 is the angle of refraction of the wave in air

Solving for the angle of refraction,

sin \theta_2 = \frac{n_1 sin \theta_1}{n_2}=\frac{(1.33) sin 35^{\circ}}{1.00}=0.763\\\theta_2 = sin^{-1} (0.763)=49.7^{\circ}

6 0
3 years ago
Read 2 more answers
A 7.0-kg rock is subject to a variable force given by the equation f(x)=6.0n−(2.0n/m)x+(6.0n/m2)x2 if the rock initially is at r
stealth61 [152]
For Newton's second law, the force is equal to the product between the mass and the acceleration of the rocket:
F=ma
From which we can rewrite the acceleration as
a(x)= \frac{F}{m} =  \frac{1}{m} (6-2x+6x^2)
where m=7.0 kg.

The velocity of the rocket is the derivative of the acceleration:
v(x) =  \frac{1}{m} (-2+12 x)
and if we substitute x=9.0 m, we find the rocket velocity after 9.0 m:
v(9)= \frac{1}{7}(-2+12\cdot 9)=15.1 m/s

4 0
3 years ago
Solar panels convert light energy from sunlight into electrical energy. What material is most likely used in solar panels, and w
klemol [59]

Answer:

A metalloid is used because it is a semiconductor and can become more conductive when more light shines on it

Explanation:

The material used in a solar panel is a metalloid. It can often become conductive when more light shines on it.

Metalloids have properties that straddles between those of metals and non-metals.

In essence, they can be conductive or not under certain conditions.

The most important property they exhibit is that they can become more conductive when more light shines on them. This way more electrons are produced.

3 0
3 years ago
Read 2 more answers
Find the moment of inertia about each of the following axes for a rod that is 0.360 {cm} in diameter and 1.70 {m} long, with a m
mamaluj [8]

The complete question is;

Find the moment of inertia about each of the following axes for a rod that is 0.36 cm in diameter and 1.70m long, with a mass of 5.00 × 10 ^(−2) kg.

A) About an axis perpendicular to the rod and passing through its center in kg.m²

B) About an axis perpendicular to the rod and passing through one end in kg.m²

C) About an axis along the length of the rod in kg.m²

Answer:

A) I = 0.012 kg.m²

B) I = 0.048 kg.m²

C) I = 8.1 × 10^(-8) kg.m²

Explanation:

We are given;

Diameter = 0.36 cm = 0.36 × 10^(−2) m

Length; L = 1.7m

Mass;m = 5 × 10^(−2) kg

A) For an axis perpendicular to the rod and passing through its center, the formula for the moment of inertia is;

I = mL²/12

I = (5 × 10^(−2) × 1.7²)/12

I = 0.012 kg.m²

B) For an axis perpendicular to the rod and passing through one end, the formula for the moment of inertia is;

I = mL²/3

So,

I = (5 × 10^(−2) × 1.7²)/3

I = 0.048 kg.m²

C) For an axis along the length of the rod, the formula for the moment of inertia is; I = mr²/2

We have diameter = 0.36 × 10^(−2) m, thus radius;r = (0.36 × 10^(−2))/2 = 0.18 × 10^(−2) m

I = (5 × 10^(−2) × (0.18 × 10^(−2))^2)/2

I = 8.1 × 10^(-8) kg.m²

3 0
3 years ago
The unit for measuring electric power is the <br> A. ampere.<br> B. volt.<br> C. ohm.<br> D. watt.
Drupady [299]
The correct answer is D: Watt. This unit was named after James Watt, and is used to express the equivalent of one joule per second in energy. In experiments and on the packaging for electrical products such as light-bulbs, the measurement will usually be written in its abbreviated format: W.
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6 0
3 years ago
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