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oksano4ka [1.4K]
3 years ago
8

Explain why asleel meedle does not csink on water​

Physics
1 answer:
Juli2301 [7.4K]3 years ago
5 0

Answer:

upthrust

Explanation:

i think it does not sink in water because of the force pulling it upwards

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Can someone please help me with this question?
dexar [7]
The answer is B because, the farther the goes the speed starts to decrease and stops it depends on the frequency of the wave.
5 0
4 years ago
A ball was dropped from a height of 10 feet. Each time it hits the ground, it bounces 4/5 of its previous height. Find the total
Shtirlitz [24]

Answer:

d = 90 ft

Explanation:

As we know that after each bounce it reaches to 4/5 times of initial height

so we can say

h_2 = \frac{4}{5}h

so the distance covered is given as

d = h + 2(\frac{4}{5}h) + 2(\frac{4}{5})^2h + 2(\frac{4}{5})^3h........

here we know that

h = 10 feet

d = h + 2(\frac{4}{5}h)(1 + \frac{4}{5} + (\frac{4}{5})^2 + ...........)

d = 10 + 2(\frac{4}{5}(10))(\frac{1}{1 - \frac{4}{5}})

d = 90 ft

8 0
3 years ago
Which statement describes the relationship between voltage and current
DaniilM [7]

Answer:

Ohm's Law. The relationship between voltage, current, and resistance is described by Ohm's law. This equation, i = v/r, tells us that the current, i, flowing through a circuit is directly proportional to the voltage, v, and inversely proportional to the resistance, r.

Explanation:

6 0
4 years ago
Which of the following devices could be used to create a position--time graph for an object? 
pickupchik [31]
D none of the above

all of them is related to energy and motion , not to positioning.
6 0
4 years ago
A hydraulic press has one piston of diameter 4.0 cm and the other piston of diameter 8.0 cm. What force must be applied to the s
yan [13]

Answer:

The  force is F_1  = 400.8 \  N

Explanation:

From the question we are told that

   The first  diameter is  d_1 =  4.0 \ cm =  0.04 \ m

   The second diameter is  d_2  =  8.0 \ cm  = 0.08 \  m

   

Generally the first area is  

         A_1  =  \pi  * \frac{d^2_1 }{4}

=>      A_1  = 3.142  * \frac{0.04^2}{4}

=>       A_1  =  0.00126 \ m^2

The  second area is  

     A_2 =  \pi  * \frac{d^2_2 }{4}

     A_2  = 3.142  * \frac{0.08^2}{4}

     A_2  =  0.00503 \ m^2

For a hydraulic press the pressure at both end must be equal .

Generally  pressure is mathematically represented as

    P =  \frac{F}{A}

=>  

   \frac{F_1}{A_1 }  =  \frac{F_2}{A_2 }

=>   F_1  =  \frac{1600}{0.00503}  *  0.00126

=>    F_1  = 400.8 \  N

8 0
3 years ago
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