What is the oxidation state of beryllium
1 answer:
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Answer:
The inventors claim is not real
a) No the the freezer cannot operate in such conditions
Explanation:
From the question we are told that
The power input is
The rate of heat transfer
The temperature of the freezer content is
The ambient temperature is
Generally the coefficient of performance of a refrigerator at idea conditions is mathematically represented as
substituting values
Generally the coefficient of performance of a refrigerator at real conditions is mathematically represented as
substituting values
Now given that the COP of an ideal refrigerator is less that that of a real refrigerator then the claims of the inventor is rejected
This is because the there are loss in the real refrigerator cycle that are suppose to reduce the COP compared to an ideal refrigerator cycle where there no loss that will reduce the COP