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algol [13]
2 years ago
12

Use the Periodic Table to determine the shape of the molecule represented by the following formulas.

Chemistry
1 answer:
neonofarm [45]2 years ago
3 0

Answer:

the answer is tetahedal and the next one is trigonal pyramidal

Explanation:

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A bubble of helium gas has a volume of 0.65 L near the bottom of a large
Flura [38]

Answer:

0.73L

Explanation:

The following data were obtained from the question :

V1 = 0.65 L

P1 = 3.4 atm

T1 = 19°C = 19 + 273 = 292K

V2 =?

P2 = 3.2 atm

T2 = 36°C = 36 + 273 = 309K

The bubble's volume near the top can be obtain as follows:

P1V1 /T1 = P2V2 /T2

3.4 x 0.65/292 = 3.2 x V2 /309

Cross multiply to express in linear form as shown below:

292 x 3.2 x V2 = 3.4 x 0.65 x 309

Divide both side by 292 x 3.2

V2 = (3.4 x 0.65 x 309) /(292 x 3.2)

V2 = 0.73L

Therefore, the bubble's volume near the top is 0.73L

8 0
3 years ago
You are given two fatlike solid substances and determine that sample a has a higher melting point than sample
Alchen [17]
Given that <span>sample a has a higher melting point than sample
b. Therefore, sample a is a longer chain of a </span><span>fatlike solid substance. It could also be that the bonds present in sample a is much stronger which will require more energy to break. Hope this answers the question.</span>
5 0
2 years ago
What amount of energy is required to change a spherical drop of water with a diameter of 1.80 mm to three smaller spherical drop
Gekata [30.6K]
This is a straightforward question related to the surface energy of the droplet. 

<span>You know the surface area of a sphere is 4π r² and its volume is (4/3) π r³. </span>

<span>With a diameter of 1.4 mm you have an original droplet with a radius of 0.7 mm so the surface area is roughly 6.16 mm² (0.00000616 m²) and the volume is roughly 1.438 mm³. </span>

<span>The total surface energy of the original droplet is 0.00000616 * 72 ~ 0.00044 mJ </span>

<span>The five smaller droplets need to have the same volume as the original. Therefore </span>

<span>5 V = 1.438 mm³ so the volume of one of the smaller spheres is 1.438/5 = 0.287 mm³. </span>

<span>Since this smaller volume still has the volume (4/3) π r³ then r = cube_root(0.287/(4/3) π) = cube_root(4.39) = 0.4 mm. </span>

<span>Each of the smaller droplets has a surface area of 4π r² = 2 mm² or 0.0000002 m². </span>

<span>The surface energy of the 5 smaller droplets is then 5 * 0.000002 * 72.0 = 0.00072 mJ </span>
<span>From this radius the surface energy of all smaller droplets is 0.00072 and the difference in energy is 0.00072- 0.00044 mJ = 0.00028 mJ. </span>

<span>Therefore you need roughly 0.00028 mJ or 0.28 µJ of energy to change a spherical droplet of water of diameter 1.4 mm into 5 identical smaller droplets. </span>
7 0
3 years ago
How many grams of zinc sulfide are used to produce 1.28 grams of zinc oxide?
Lostsunrise [7]

Answer:

0.012288122055459

Explanation:

i might be wrong

6 0
2 years ago
A solution contains one or more of the following ions: Ag+, Ca2+, and Fe2+. When sodium chloride is added to the solution, no pr
Ksju [112]

Answer:

the ion present in the original solution is Ca2+

Explanation:

Precipitation reactions occur when cations and anions in aqueous solution combine to form an insoluble ionic solid called a precipitate.

<u>Step1</u> : If we add Nacl to the solution, there is no precipitate formed

⇒The only possible ion that can form a precipate with Cl- is Ag+; since there is no precipitate formed, Ag+ is not present

<u>Step2</u> : If we add Na2SO4 to the solution, a white precipitate is formed

The possible ions to bind at SO42- are Ca2+ and Fe2+

But the white precipitate formed, points in the direction of Ca2+

⇒This means calcium is present

<u>Step3</u> : If we add Na2CO3 to the filtered solution, there is a precipate formed

Ca2+ will bind also with CO32- and form a precipitate

So the ion present in the original solution is Ca2+

6 0
3 years ago
Read 2 more answers
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