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likoan [24]
3 years ago
11

A trout jumps, producing waves on the surface of a 0.8-mdeep mountain stream. If it is observed that the waves do not travel ups

tream, what is the minimum velocity of the current?
Physics
1 answer:
alina1380 [7]3 years ago
5 0

Answer:

The value is v  =  2.8 \  m/s

Explanation:

From the question we are told that  

     The depth of the mountain is  d =  0.8 \  m

Generally the  velocity of the surface  wave  is mathematically represented as

        v =   \sqrt{ g * d }      

=>      v =   \sqrt{ 9.8 * 0.8  }    

=>      v =   2.8 \  m/s

Generally using the Froude number is mathematically represented as

          Fr = \frac{ V }{ v }

Here V is the velocity of the current

 Given that  the waves do not travel upstream, then the flow of the current is  supercritical which means that

            \frac{ V }{ v } > 1

=>         V  > v

=>         V  > 2.8 \  m/s

Hence the minimum velocity of the current  is  

            v  =  2.8 \  m/s

This because the velocity of the  current is greater velocity of the surface  wave , so minimum will be like the lowest possible value of  V  which is v

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A less massive moving object has an elastic collision with a more massive object that is not moving. Compare the initial velocit
stepladder [879]

Assume that the small-massed particle is m and the heavier mass particle is M.

Now, by momentum conservation and energy conservation:

   mv = mv_{m} + Mv_{M}

   mv^{2} = mv^{2}_{m} + Mv^{2}_{M}

Now, there are 2 solutions but, one of them is useless to this question's main point so I excluded that point. Ask me in the comments if you want the excluded solution too.

   v_{m} = v\frac{m - M}{m + M}\\\\\\v_{M} = v\frac{m + M}{m + M}\\

So now, we see that v_{m} < 0 and v_{M} > 0. So therefore, the smaller mass recoils out.

Hope this helps you!

Bye!

7 0
3 years ago
A 0.10 kg mass is oscillating at a small angle from a light string of length 0.10 m.
cupoosta [38]

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tough

Explanation:

5 0
2 years ago
17 copper wires of length l and diameter d are connected in parallel to form a single composite conductor of resistance R. What
Lubov Fominskaja [6]

Answer:

\frac{D}{d} = 4.12

Explanation:

As we know that resistance of one copper wire is given as

r = \rho \frac{L}{a}

here we know that

a = \pi (\frac{d}{2})^2

now we have

r = \rho \frac{L}{\pi (\frac{d^2}{4})}

r = \rho \frac{4L}{\pi d^2}

now we know that such 17 resistors are connected in parallel so we have

R = \frac{r}{17}

R = \rho \frac{4L}{17 \pi d^2}

Now if a single copper wire has same resistance then its diameter is D and it is given as

R = \rho \frac{4L}{\pi D^2}

now from above two equations we have

\rho \frac{4L}{\pi D^2} = \rho \frac{4L}{17 \pi d^2}

D^2 = 17 d^2

now we have

\frac{D}{d} = 4.12

3 0
2 years ago
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