Electromagnetic waves or EM waves are waves that are created as a result of vibrations between an electric field and a magnetic field. ... They are hence known as 'electromagnetic' waves. The electric field and magnetic field of an electromagnetic wave are perpendicular (at right angles) to each other.

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7 0

3 years ago

An 800-kHz radio signal is detected at a point 4.5 km distant from a transmitter tower. The electric field amplitude of the sign

saul85 [17]

Answer:

$2.1\times 10^{-9} T$

Explanation:

We are given that

Frequency,f=800KHz= $800\times 10^{3} Hz$

$1kHz=10^{3} Hz$

Distance,d=4.5 km= $4.5\times 10^{3} m$

1 km=1000 m

Electric field,E=0.63V/m

We have to find the magnetic field amplitude of the signal at that point.

$c=3\times 10^8 m/s$

We know that

$B=\frac{E}{c}$

$B=\frac{0.63}{3\times 10^8}=0.21\times 10^{-8} T$

$B=2.1\times 10^{-9} T$

8 0

4 years ago

An arrow in flight has an initial velocity of 65 meters per second, and 10 seconds later, it has a velocity of 35 meters per sec

Sergeu [11.5K]

To find the acceleration, we would need to use the equation acceleration= final velocity- initial velocity/elapsed time. Since the final velocity is 35 and the initial velocity is 65, we can subtract 65 from 35 first, which gives us -30. Then if we divide that by the elapsed time, which is 10, we get -3. Your acceleration is -3 meters per second.

Hope this helps! :D

3 0

3 years ago