Answer:
a) 39.6 m/s b) 4123 N
Explanation:
a) At the top of the loop, all of the forces point downwards (force of gravity and normal force).
Fnet=ma
ma=m(v^2/R) (centripetal acceleration)
mg=m(v^2/R)
m cancels out (this is why pilot feels weightless) so,
g=(v^2/R)
9.8 m/s^2 = v^2/160 m
v^2=1568 m^2/s^2
v=39.6 m/s
b) At the bottom of the loop, the normal force and the force of gravity point in opposite directions. The normal force is the weight felt.
Convert 300 km/hr to m/s
300 km/hr=83.3 m/s
Convert pilot's weight into mass:
760 N = 77.55 kg
Fnet=ma
n-mg=m(v^2/R)
n=(77.55 kg)(((83.3 m/s)^2)/160 m)+(77.55 kg)(9.8 m/s^2)
n=3363.2 N+760 N=4123 N
Answer: 9000 kgm/s
Explanation:
Mass of car = 1500 kg
Speed by which car moves = 6 m/s. Momentum of the car = ?
Recall that:
Linear momentum = Mass x Speed
= 1500kg x 6m/s
= 9000 kgm/s
Thus, the linear momentum of the car is 9000 kgm/s
The sentence can be completed as follows:
"Electricity is the movement of charges from one atom to another along a conductor."
The movement of the the charges is due to the presence of a potential difference across the conductor, which pushes the charges. More specifically, in normal conductors, the carriers of electricity are the electrons. Therefore we can rewrite the sentence as
"Electricity is the movement of electrons from one atom to another along a conductor."
Any force of 29.4 Newtons or greater can do it.
