Answer:
(a). 4°C, (b). 2.4M, (c). 11.1 g, (d). 89.01 g, (e). 139.2 g and (f). 58 g/mol.
Explanation:
Without mincing words let's dive straight into the solution to the question.
(a). The freezing point depression can be Determine by subtracting the value of the initial temperature from the final temperature. Therefore;
The freezing point depression = [ 1 - (-3)]° C = 4°C.
(b). The molality can be Determine by using the formula below;
Molality = the number of moles found in the solute/ solvent's weight(kg).
Molality = ( 11.1 / 58) × (1000)/ ( 90.4 - 11.1) = 2.4 M.
(c). The mass of acetone that was in the decanted solution = 11.1 g.
(d). The mass of water that was in the decanted solution = 89.01 g.
(e). 2.4 = x/ 58 × (1000/1000).
x = 2.4 × 58 = 139.2 g.
(f). The molar mass of acetone = (12) + (1 × 3) + 12 + 16 + 12 + (1 x 3) = 58 g/mol.
Answer: The moles of carbon needed will be, 13.8 moles
Explanation: Moles of = 5.52 mole
Now we have to calculate to moles of carbon.
The given balanced chemical reaction is,
From the balanced chemical reaction, we conclude that
As, 2 mole of react to give 5 moles of carbon
So, 5.52 mole of react to give moles of carbon
Therefore, the moles of carbon needed will be, 13.8 moles
It has 2 valence electrons
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Answer:
Some examples of homoatomic molecules are hydrogen gas, and oxygen gas and some examples of heteroatomic molecules are water, methane
Explanation:
Answer:
B.
Explanation:
Increased stability in fluoride ion.
