Answer:
Option-B (Carbon and Silicon)
Explanation:
Among the given pairs only carbon and silicon have the most similar properties. This is because,
Sodium and Magnesium belong to different groups. Sodium present in Group I has one electron in its valence shell and capable of transferring only one electron while, Magnesium present in Group II have two electrons in its valence shell and is capable of donating two electrons. Hence, both show different properties.
Example:
2 Na + Cl₂ → NaCl
Mg + Cl₂ → MgCl₂
As shown in reactions when Sodium and Magnesium are treated with Cl₂ they give a products with different proportions.
Carbon and Silicon show almost same properties because both belong to Group IV hence both are capable of forming four bonds. Also, they share the same property of self linkage in making a long chains.
Argon and Chlorine also belong to two different groups. Argon is present in Group VIII (Noble Gases) and Chlorine is present in Group VII (Halogens). Hence, Argon is an inert specie which is non reactive while Chlorine gives different reaction easily.
Potassium and Calcium belong to different groups. Potassium present in Group I has one electron in its valence shell and capable of transferring only one electron while, Calcium present in Group II have two electrons in its valence shell and is capable of donating two electrons. Hence, both show different properties.
Example:
2 K + Cl₂ → KCl
Ca + Cl₂ → CaCl₂
As shown in reactions when Potassium and Calcium are treated with Cl₂ they give a products with different proportions.
What are you asking on this question?
Answer:
it is possible to remove 99.99% Cu2 by converting it to Cu(s)
Explanation:
So, from the question/problem above we are given the following ionic or REDOX equations of reactions;
Cu2+ + 2e- <--------------------------------------------------------------> Cu (s) Eo= 0.339 V
Sn2+ + 2e- <---------------------------------------------------------------> Sn (s) Eo= -0.141 V
In order to convert 99.99% Cu2 into Cu(s), the equation of reaction given below is needed:
Cu²⁺ + Sn ----------------------------------------------------------------------------> Cu + Sn²⁺.
Therefore, E°[overall] = 0.339 - [-0.141] = 0.48 V.
Therefore, the change in Gibbs' free energy, ΔG° = - nFE°. Where E° = O.48V, n= 2 and F = 96500 C.
Thus, ΔG° = - 92640.
This is less than zero[0]. Therefore, it is possible to remove 99.99% Cu2 by converting it to Cu(s) because the reaction is a spontaneous reaction.
Answer:
a) 24.31 g
b) 16.69 g
Explanation:
A mixture of CO2 and Kr weighs 41.0 g and exerts a pressure of 0.729 atm in its container.
After the CO2 is completely removed by absorption with NaOH(s), the pressure in the container is 0.193 atm.
Therefore, Pressure of Kr = 0.193 atm
Pressure of CO2 = 0.729 - 0.193 = 0.536 atm
Their mole fraction can be also determined as follows:
CO2 = 
CO2 = 
= 0.735
Also; for Kr ; we have
Kr = 
Kr = 0.265
Molar mass of CO2 = 44 g/mol
Molar mass of Kr = 83.78 g/mol
Mass of CO2 = mole fraction * molar mass = 0.735 * 44 = 32.34
Mass of Kr = 0.265 * 83.78 = 22.20
Total mass = 32.34 +22.20 = 54.54
The Percentage of gas in mixture is as follows:
% CO2 = 
* 100 %
= 0.5930
= 59.30%
(a) Mass of CO2 in mixture = 0.5930* 41 g = 24.31 g
% Kr =
* 100 %
= 0.407
= 40.70 %
(b) Mass of Kr in mixture = 0.407 * 41 = 16.69 g
A variable that stays the same
