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coldgirl [10]
3 years ago
13

Is a polyatomic ion electrically neutral?

Chemistry
2 answers:
marin [14]3 years ago
7 0

No "ion" is electrically neutral.  If it's an ion, then it's charged.


charle [14.2K]3 years ago
6 0
Answer: Yes I think it is (I'm kind of wondering the same thing)
You might be interested in
In scientific notation the radius of the sun is ......times 10..... kilometers
Alborosie

Answer:

The radius of the sun is 7x10^5 kilometers, and that of the Earth is about 6.4x10^3 kilometers. Use scientific notation to show that the Sun's radius is about 100 times the Earth's radius. The Sun's radius is 10^10 the Earth's radius.

3 0
3 years ago
Determine the mass of CaCO3 required to produce 40.0 mL CO2 at STP. Hint use molar volume of an ideal gas (22.4 L)
cupoosta [38]

Answer:

m_{CaCO_3}=0.179gCaCO_3

Explanation:

Hello,

In this case, since the undergoing chemical reaction is:

CaCO_3(s)\rightarrow CaO(s)+CO_2(g)

The corresponding moles of carbon dioxide occupying 40.0 mL (0.0400 L) are computed by using the ideal gas equation at 273.15 K and 1.00 atm (STP) as follows:

PV=nRT\\\\n=\frac{PV}{RT}=\frac{1.00 atm*0.0400L}{0.082\frac{atm*L}{mol*K}*273.15 K})=1.79x10^{-3} mol CO_2

Then, since the mole ratio between carbon dioxide and calcium carbonate is 1:1 and the molar mass of the reactant is 100 g/mol, the mass that yields such volume turns out:

m_{CaCO_3}=1.79x10^{-3}molCO_2*\frac{1molCaCO_3}{1molCO_2} *\frac{100g CaCO_3}{1molCaCO_3}\\ \\m_{CaCO_3}=0.179gCaCO_3

Regards.

3 0
4 years ago
A 27.86 ml sample of 0.1744 m hno3 is tirades with 29.4ml of a job solution. What is the molarity of the koh
Arte-miy333 [17]

Answer:

0.165 mol·L⁻¹

Explanation:

1. Write the <em>chemical equation</em> for the reaction.

HNO₃ + KOH ⟶ KNO₃ + H₂O

===============

2. Calculate the <em>moles of HNO₃</em>

c = n/V                                               Multiply each side by V and transpose

n = Vc

V = 0.027 86 L

c = 0.1744 mol·L⁻¹                             Calculate the moles of HNO₃

Moles of HNO₃ = 0.027 86 × 0.1744

Moles of HNO₃ = 4.859 × 10⁻³ mol HNO₃

===============

3. Calculate the <em>moles of KOH </em>

1 mol KOH ≡ 1 mol HNO₃                 Calculate the moles of KOH

Moles of KOH = 4.859 × 10⁻³× 1/1

Moles of KOH = 4.859 × 10⁻³ mol KOH

===============

4. Calculate the <em>molar concentration</em> of the KOH

V = 29.4 mL = 0.0294 L                   Calculate the concentration

c = 4.859 × 10⁻³/0.0294

c = 0.165 mol·L⁻¹

4 0
4 years ago
Gallium has two naturally occurring isotopes with the following masses and natural abundances: Isotope Mass ( amu ) Abundance (%
ICE Princess25 [194]
The formula for determination of atomic mass given the mass of isotopes and relative abundance is:

Ar = ∑(mass * abundance) / 100
Ar = (68.92558 * 60.108 + 70.92470 * 39.892) / 100
Ar = 69.72306

The atomic mass of gallium is 69.72306 amu
4 0
3 years ago
Menthol, the substance we can smell in mentholated cough drops, is composed of C, H, and O. A 0.1005 g sample of menthol is comb
larisa [96]

Answer:

molecular formula = C₁₀H₂₀O

Explanation:

the carbon dioxide is obtained on combustion from an organic molecule due to reaction of carbon with oxygen and water is formed due to reaction of hydrogen with oxygen to form water.

The reactions are:

C+O_{2}--> CO_{2}\\H_{2}+ 0.5O_{2} --->H_{2}O

From above equations

i) 44g of carbon dioxide is formed from 12g of carbon

Therefore 0.2829g of carbon dioxide must be formed from = \frac{12X0.2829}{44}=0.077 gramsof carbon

ii) 18g of water is formed from 2 grams of hydrogen

Therefore 0.1159 grams of water must be formed from =

\frac{2X0.1159}{18}= 0.0128ghydrogen

Total weight of sample taken = 0.1005

so mass of oxygen = 0.1005-(0.077+0.0129)=0.0106 g

moles of carbon = mass / atomic mass = 0.077/12=0.00641

moles of hydrogen = mass /atomic mass = 0.0128/1=0.0128

moles of oxygen = mass / atomic mass =0.0106/ 16=0.00066

Let us divide all the moles with the smallest one

moles of carbon = 0.00641 / 0.00066 = 10 (approx)

moles of hydrogen = 0.0128/0.00066 = 20 (approx)

moles of oxygen = 0.00066/0.00066 = 1

Empirical formula of menthol = C₁₀H₂₀O

Empirical mass =10X12 + 20X1 + 16= 156

Which is equal to molar mass hence the empirical formula = molecular formula

5 0
4 years ago
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