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3 years ago

8

If the experiment were repeated using a cuvettes with a path length of 2.0 cm, how would that affect the absorbance values for t

he Co2 solutions (if at all), assuming all of the concentrations remained unchanged?

1 answer:

inessss [21]3 years ago

5 0

Answer:

..............................

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Based on bond type, which compound has the

lorasvet [3.4K]

Based on bond type, CaCI2 has the highest melting point.

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4 years ago

PLZZZ HELP I NEED ANSWER ASAP THE FIRST ANSWER GETS BRAINLIEST

zalisa [80]

Answer:through the conduction from magma to water and rocks

Explanation:

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3 years ago

How many molecules of sodium oxide will be created if 187 grams of oxygen reacts with excess sodium? 4na o2 -> 2na2o

Leona [35]

Molecules of sodium oxide will be created if 187 grams of oxygen reacts with excess sodium will be 7.04 × 10 ²⁴ molecules.

Sodium oxide is Na₂O which is formed due to the reaction of sodium and oxygen.

Given,

Balanced chemical equation is :

4 Na(s) + O₂ (g) → 2Na₂O (s)

Now, the Mole ratio of O₂ and Na₂O is 1 mol O₂: 2 mol Na₂O

Molar mass O₂ = 32.00 g/mol

Now, let's find out the Number of moles of O₂ present in 187 grams of oxygen,

Number of moles of O₂ = Given mass in grams / molar mass of O₂

Number of moles of O₂ = 187 g / 32.00 g/mol

Number of moles of O₂ = 5.844 mol

Since, we know the Proportion is 1 mol O₂ : 2 mol Na₂O

Now, Number of moles of Na₂O required is,

2 mol Na₂O / 1 mol O₂ = 5.844 mol O₂ / x

x = 5.844 mol O₂ (2 mol Na₂O / 1 mol O₂)

x = 11.688 mol Na₂O

To calculate the Number of molecules of sodium oxide,

Number of molecules = Number of moles × Avogadro's number

Number of molecules = 11.688 mol × 6.022 × 10²³ molecules/mol =

Number of molecules = 7.04 × 10 ²⁴ molecules

Hence, the Number of molecules of sodium oxide required is 7.04 × 10²⁴ molecules.

Learn more about Sodium oxide here,

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2 years ago

PLEASE HELP ME!<br> Determine the number of atoms in 4.27 g gold.

solmaris [256]

This can be done with some simple dimensional analysis. First you convert your gram of gold into moles of gold There are 196.97 grams of gold for every one mole of gold so you divide 4.27 by 196.67 to get 0.0217 moles of gold. You then multiply the moles of gold by Avogadro's number, 6.02 X 10^23. Avogadro's number indicates the number of atoms in one mole. Therefore, there are 1.307 X 10^22 atoms in 4.27 grams of gold.

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3 years ago

Potassium hydroxide is very soluble in water, resulting in extremely basic solutions. A 121g sample KOH is dissolved in water at

nataly862011 [7]

Answer:

15.33

Explanation:

Given parameters:

Mass of KOH = 121g

Volume of solution = 100mL = 0.1dm³

Molar mass of KOH = 56.11g/mol

Unknown:

pH of the solution = ?

Solution:

To find the pH, we must first know the concentration of the solution obtained by mixing KOH up to this volume.

This can be done by finding the molarity of the solution.

Molarity = $\frac{number of moles }{volume of solution}$

Number of moles of KOH = $\frac{mass}{molar mass}$ = $\frac{121}{56.11}$ = 2.16mole

Input parameters;

Molarity of solution = $\frac{2.16}{0.1}$ = 21.6moldm⁻³

KOH → OH⁻ + K⁺

21.6 21.6 21.6

In the solution we have 21.6moldm⁻³ of OH⁻ which is need to find the pH;

pOH = -log₁₀(OH⁻)

pOH = -log₁₀21.6

pOH = -1.33

Since pH + pOH = 14

pH = 14 - (-1.33) = 15.33

3 0

4 years ago