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3 years ago

Answer with explanation!!!

Physics

1 answer:

adell [148]3 years ago

8 0

Answer:

The light enters the box along the normal to the side of the box or perpendicularly to the box's surface

Therefore, the light is expected to travel straight through the box

However, when a rectangular glass prism is placed inside the box, the light can then be refracted to pass through the box in the given path as shown

Light bends towards the normal when passing from a less dense medium to a denser medium with larger refractive index and vice versa

Therefore, when the glass prism with a larger refractive index than air is inclined with the top part further away from the incident beam and the bottom part closer to the incident beam as shown, the refracted ray through the box will be shifted downwards as shown in the drawing created with Microsoft Visio

Explanation:

$Refractive \ index, n = \dfrac{sin(i)}{sin(r)}$

Where;

i = The angle between the incidence light and the normal line

r = The angle between the refracted light and the normal line

n = The refractive index

When n > 1 is large, we have, ∠i > ∠r and the light is bent towards the normal when moving from a less dense medium to a denser medium and vice versa.

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3 years ago

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jek_recluse [69]

when the apple moves in a horizontal circle, the tension force in the string provides the necessary centripetal force to move in circle. the tension in the string is given as

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3 years ago

Calculate the frequency if the number of revolutions is 300 and the paired poles are 50.

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2 years ago

Assume that the position vector of A is r=i+j+k . Determine the moment about the origin O if the force F=(1)i+(0)j+(5)k . The mo

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Answer:

M₀ = 5i - 4j - k

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Using the cross product method, the moment vector(M₀) of a force (F) is about a given point is equal to cross product of the vector A from the point (r) to anywhere on the line of action of the force itself. i.e

M₀ = r x F

From the question,

r = i + j + k

F = 1i + 0j + 5k

Therefore,

M₀ = (i + j + k) x (1i + 0j + 5k)

M₀ = $\left[\begin{array}{ccc}i&j&k\\1&1&1\\1&0&5\end{array}\right]$

M₀ = i(5 - 0) -j(5 - 1) + k(0 - 1)

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M₀ = 5i - 4j - k

Therefore, the moment about the origin O of the force F is

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3 years ago

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slavikrds [6]

Answer:

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3 years ago