Answer:
12
Explanation:
A solar eclipse occurs when the moon in between the sun and the earth. Since in reality, the moons orbit is inclined, this aligning doesnt occur often. But if the orbit of the moon were in the same plane as the earth orbit, and since the moon orbits the earth once a month, the three objects would align every month. This makes it 12 times in a year.
For my first part it like that as we all know that flux density is the charge per unt area here charge is 60uc so divide 60uc by (4*pi*r2) we get D= 7.06*10^-5 c/m2. NOW given is portion with r=26cm theta= 0 to pi/2 and phi = 0 to pi/2 calculate required region area with formula =double integral(r^2sintheta dtheta dphi) we get =.106m^2 now multiply D*Required region we get 7.5uc M I RIGHT PLZ tell me
100 J of kinetic energy but no gravitational potential energy if GPE of the ground is assumed to be zero.
<h3>Explanation</h3>
Kinetic Energy
The ball carries kinetic energy for being in motion. The size of that energy is given as:
where
- is the mass of the object, and
- is its speed.
SI units:
- : joules.
- : kilograms.
- : meters per second.
For this ball:
.
Gravitational Potential Energy
Whether the ball carries gravitational potential energy depends on the point of zero potential energy. The ball would carry GPE if the point of zero potential energy is chosen underground. However, the question emphasizes that the ball is "on the ground," which <em>implies</em> that the ground is the reference with a GPE of zero.
The gravitational field near the Earth's surface is constant. As a result, GPE is proportional to height relative to the ground (or the point of zero GPE). The ball is on the ground. Its height is zero. As a result, its GPE is also zero.
Answer:
The load that can be lifted is equal to the weight W = F2A1/A2
Explanation:
According to Pascal principle which states that the pressure applied to a liquid confined in a container will be transmitted equally to all other parts of the container.
Since pressure = Force/Area
The force F2 applied at one end of the piston will generate a pressure of F2/A2. This pressure generated will be transmitted to the other end of the piston of area A1 to lift the load through a distance.
The piston where the load is will experience an upward force F1 which is equal to Pressure × Area.
The pressure experienced by the load is applied by force F2.
Force on the load = (Pressure exerted by Force F2) × Area at the larger end A1
Force on the load = F2/A2 × A1
Since the load experiences a weight W
The weight will be equal to the force on the load which is to be lifted i.e W =Force on the load.
W = F2A1/A2
The load that can be lifted is equal to the weight W = F2A1/A2