Answer:
2.5 moles
Explanation:
Number of moles = MassMolar mass
= 80⋅g32.06⋅g⋅mol−1 = ??mol
Note that sulfur likely exists in its elemental state as S8. I am perfectly justified in treating sulfur as S. The number of sulfur atoms is the same in each case.
Answer:

Explanation:
No atoms of Mg have a mass of 24.3050 u. That is the average mass of all the isotopes of Mg.
However, the most common isotope of Mg is ₁₂²⁴Mg (mass = 23.99 u)
The atomic number of Mg is 12. It has 12 protons.
The atomic mass of ²⁴Mg is 24. That's the total number of protons and neutrons.
p + n = 24
12 + n = 24
n = 12
An atom of ²⁴Mg has 12 neutrons.
If the atom is neutral, the number of electrons equals the number of protons.
e = p = 12

Answer:
lice, mosquito
Explanation:
both are examples of parasitism
edit: wait nvm i thought this was bio
we will use the root mean squared speed of oxygen formula
v= (3RT) / M
T= vM/3R
where
v =1.12x104 m/s; velocity
R= (8.31447 kg m2 s-2 K-1 mol-1) gas constant
M = 0.0319988 kg/mol; molar mass of oxygen
substituting the given values, we will get
T(K)= 14.37K or -258.78 C
Oxygen molecules speed of 1.12x104 m/s is at temperature -258.78C.
<span>n this order, Ď=1.8gmL, cm=0.5, and mole fraction = 0.9
First, let's start with wt%, which is the symbol for weight percent. 98wt% means that for every 100g of solution, 98g represent sulphuric acid, H2SO4.
We know that 1dm3=1L, so H2SO4's molarity is
C=nV=18.0moles1.0L=18M
In order to determine sulphuric acid solution's density, we need to find its mass; H2SO4's molar mass is 98.0gmol, so
18.0moles1Lâ‹…98.0g1mole=1764g1L
Since we've determined that we have 1764g of H2SO4 in 1L, we'll use the wt% to determine the mass of the solution
98.0wt%=98g.H2SO4100.0g.solution=1764gmasssolution→
masssolution=1764gâ‹…100.0g98g=1800g
Therefore, 1L of 98wt% H2SO4 solution will have a density of
Ď=mV=1800g1.0â‹…103mL=1.8gmL
H2SO4's molality, which is defined as the number of moles of solute divided by the mass in kg of the solvent; assuming the solvent is water, this will turn out to be
cm=nH2SO4masssolvent=18moles(1800â’1764)â‹…10â’3kg=0.5m
Since mole fraction is defined as the number of moles of one substance divided by the total number of moles in the solution, and knowing the water's molar mass is 18gmol, we could determine that
100g.solutionâ‹…98g100gâ‹…1mole98g=1 mole H2SO4
100g.solutionâ‹…(100â’98)g100gâ‹…1mole18g=0.11 moles H2O
So, H2SO4's mole fraction is
molefractionH2SO4=11+0.11=0.9</span>