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garik1379 [7]
3 years ago
6

chemist must prepare of hydrochloric acid solution with a pH of at . He will do this in three steps: Fill a volumetric flask abo

ut halfway with distilled water. Measure out a small volume of concentrated () stock hydrochloric acid solution and add it to the flask. Fill the flask to the mark with distilled water. Calculate the volume of concentrated hydrochloric acid that the chemist must measure out in the second step. Round your answer to significant digits.
Chemistry
1 answer:
olya-2409 [2.1K]3 years ago
3 0

Answer:

1.7mL of the stock solution

Explanation:

<em>...Must prepare 550.0mL with a pH of 1.60 at 25°C</em>

<em>...Fill a 550.0mL volumetric flask</em>

<em>...Concentrated stock of 8.0M</em>

<em>... Round the answer to 2 significant digits</em>

<em />

First, with pH we can solve [H⁺] = [HCl] concentration that we need to prepare the solution:

pH = -log[H⁺]

1.60 = -log[H⁺]

10^-1.60 = [H⁺]

0.0251M = [H⁺]

That means we need to dilute the concentrated solution from 8M to 0.0251M, that is:

8M / 0.0251M = 318.5 times

As the final volume of the solution is 550.0mL, the volume of the stock 8M HCl solution must be:

550.0mL / 318.5 times =

<h3>1.7mL of the stock solution</h3>

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I could really use some help with this question, thank you in advance!​
Taya2010 [7]
C because
Explanation Plato
6 0
2 years ago
The first word in the name of an ester is derived from the ________ used in the esterification.
oksian1 [2.3K]

The first word in the name of an ester is derived from the alcohol used in the esterification.

<h3>What is esterification?</h3>

Esterification is a chemical process where an organic acid with the formula is combined with an alcohol molecule having the chemical formula (ROH).

The process of esterification is known to produce an ester molecule and during this phenomenon is released water (H2O).

An example of an esterification reaction occurs when ethanoic acid (i.e., the active ingredient of vinegar) can react with C2H5OH (i.e., ethanol) in order to form the ethyl ethanoate molecule, which is a well-known ester molecule.

In conclusion, the first word in the name of an ester is derived from the Alcohol used in the esterification.

Learn more about esterification here:

brainly.com/question/14028062

#SPJ1

8 0
2 years ago
2Fe(OH)3 Fe2O3+3H2O how many grams of Fe2O3 are produced if 10.7 grams of Fe (OH)3 react in this way
sasho [114]

Answer: 7.98 grams of Fe_2O_3 are produced if 10.7 grams of Fe(OH)_3 are reacted.

Explanation:

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)  

Putting values in equation 1, we get:

\text{Moles of} Fe(OH)_3=\frac{10.7g}{106.87g/mol}=0.100mol  

The chemical equation for the reaction is

2Fe(OH)_3\rightarrow Fe_2O_3+3H_2O

By Stoichiometry of the reaction:

2 moles of Fe(OH)_3 produce = 1 mole of Fe_2O_3

So, 0.100 moles of Fe(OH)_3 produce= \frac{1}{2}\times 0.100=0.05mol of Fe_2O_3  

Mass of Fe_2O_3 =moles\times {\text{Molar Mass}}=0.05mol\times 159.69g/mol=7.98g  

Hence 7.98 grams of Fe_2O_3 are produced if 10.7 grams of Fe(OH)_3 are reacted.

3 0
2 years ago
An unknown triprotic acid (H3A) is titrated with NaOH. After the titration Ka1 is determined to be 0.0013 and Ka2 is determined
e-lub [12.9K]

Answer:

6.68 X 10^-11

Explanation:

From the second Ka, you can calculate pKa = -log (Ka2) = 6.187

The pH at the second equivalence point (8.181) will be the average of pKa2  and pKa3. So,

8.181 = (6.187 + pKa3) / 2

Solving gives pKa3 = 10.175, and Ka3 = 10^-pKa3 = 6.68 X 10^-11

7 0
3 years ago
What volume of chlorine gas at 27 °C, 812 mmHg, is required to react with an excess of carbon disulfide so that 5.00kJ of heat i
Kamila [148]

Answer:

The correct answer is 1.21 L.

Explanation:

Based on the given information, the reaction will be,

CS2 (l) + 3Cl2 (g) ⇒ CCl4 (l) + S2Cl2 (l)

By using the standard values of the substances, the standard enthalpy of the reaction is,

ΔH° = [(-139.5) + (-58.5) – 0 – (87.3)] kJ/mol

= -285.3 kJ/mol

The amount of heat evolved for 3 moles of chlorine reacted us 285.3 kJ.

Now the number of moles of chlorine needed to react to produce 5.00 kJ is,

= 5.00 kJ × 3 mol Cl2/285.3 kJ

= 0.0526 mol Cl2

Now the volume of chlorine gas at 27degree C and 812 mmHg will be,

Volume = 0.0526 mol Cl2 × 0.0821 Latm/mol K × 300 K/ 1.07 atm

= 1.21 L

4 0
2 years ago
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