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Scrat [10]
3 years ago
13

Why is it harder to breathe on a

Physics
1 answer:
Law Incorporation [45]3 years ago
6 0
I think it’s d but I’m not sure
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If the electric potential in a region is given by v(x)=7/x2 the x component of the electric field in that region is
lions [1.4K]

Hi there!

Recall that:
\Delta V = -\int\limits^a_b {E \cdot } \, dx

Given an electric field, the potential difference can be solved by using integration. Similarly:
E = -\frac{dV}{dx}

We can differentiate the electric potential equation to solve for the electric field.

Use the power rule:
\frac{dy}{dx} x^n = nx^{n - 1}

Differentiate the given equation.

-\frac{dV}{dx}\frac{7}{x^2} =- \frac{dV}{dx}7x^{-2} = -(-14x^{-3}) = \frac{14}{x^3}

Or:
\boxed{E(x) = \frac{14}{x^3}}

6 0
2 years ago
What is the algebraic expression for the component of the normal force in the vertical direction?
inna [77]

The algebraic expression for the component of the normal force in the vertical direction is Force= product of mass and area.

<h3>What is Force?</h3>

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction. Or, there is a specific meaning to the word "force." At this level, calling a force a push or a pull is entirely appropriate. A force is not something an object "has in it" or that it "contains." One thing experiences a force from another. There are both living things and non-living objects in the concept of a force.

To learn more about Force, visit

brainly.com/question/13014979

#SPJ4

5 0
1 year ago
A uniformly charged ring of radius 10.0 cm has a total charge of 50.0 μC Find the electric field on the axis of the ring at 30.0
Grace [21]

Answer: 4.27 *10^6 N/C

Explanation: In order to calculate the electric field along the axis of charged ring we have to use the following expression:

E=k*x/(a^2+x^2)^3/2    where a is the ring radius and x the distance to the point measured from the center of the ring.

Replacing the data we have:

E= (9* 10^9* 0.3* 50 * 10^-6)/(0.1^2+0.3^2)^3/2

then

E=4.27 * 10^6 N/C

8 0
3 years ago
Help! <br><br> I need to do this quickly!!!
umka2103 [35]
D is the answer. It is a firm statement.
8 0
3 years ago
A tank of volume 0.25 ft is designed to contain 50 standard cubic feet of air. The temperature is 80° F.Calculate the pressure i
slavikrds [6]

Answer:

The inside Pressure of the tank is 4499.12 lb/ft^{2}

Solution:

As per the question:

Volume of tank, V = 0.25 ft^{3}

The capacity of tank, V' = 50ft^{3}

Temperature, T' = 80^{\circ}F = 299.8 K

Temperature, T = 59^{\circ}F = 288.2 K

Now, from the eqn:

PV = nRT                      (1)

Volume of the gas in the container is constant.

V = V'

Similarly,

P'V' = n'RT'                       (2)

Also,

The amount of gas is double of the first case in the cylinder then:

n' = 2n

\]frac{n'}{n} = 2

where

n and n' are the no. of moles

Now, from eqn (1) and (2):

\frac{PV}{P'V'} = \frac{nRT}{n'RT'}

P' = 2P\frac{T'}{T} = 2\times 2116\times \frac{299.8}{288.2} = 4499.12 lb/ft^{2}

7 0
4 years ago
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