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Rainbow [258]
3 years ago
12

Place the following steps in order for motor control. 1. Upper motor neurons stimulate lower motor neurons. 2. Sensory informati

on is relayed back to the cerebellum so movement can be modified if needed. 3. Upper motor neurons in the premotor cortex select a motor program. 4. Lower motor neurons stimulate a skeletal muscle to contract. 5. The basal nuclei enable the thalamus to stimulate upper motor neurons of the primary cortex.
Physics
1 answer:
Alla [95]3 years ago
4 0

Answer:

3, 5, 1, 4, 2

Explanation:

When the body needs to move, certain muscles need to be stimulated in order to perform a certain movement. There is a process that is followed that starts with the brain sending a signal, and ends with the movement being performed by the body.

3. This is the first step, because a pathway needs to be established before any electric impulses can be sent. Hence, the upper motor neurons in the premotor cortex <u>need to choose a pathway</u> (known as a motor program).

5. This is the second step, because once a pathway has been established, a <u>signal needs to be sent</u> down that pathway. Hence, the basal nuclei enable the thalamus to stimulate the upper motor neurons to send an electrical impulse down the pathway.

1. This is the third step, because once the upper motor neurons have been stimulated, they send an electrical impulse to stimulate the lower motor neurons.

4. This is the forth step, because once the electrical impulse reaches the lower motor neurons, they pass the impulse to a certain group of skeletal muscles, causing them to contract.

2. This is the final step, because once the skeletal muscles have contracted, the <u>body has completed its movement</u>. However, once the body has moved, sensory information is relayed to the cerebellum to <u>ensure that the correct movement is made</u>, and if it needs to be adjusted, then the whole process will start again in order to correct the movement.

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h = 8.4

g = 9.8

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1. During the Middle Ages, armies often attacked castles using large siege engines such as the counterweight trebuchet at left.
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a. 46 m/s east

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v=u+at

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v is the velocity calculated at time t

u is the initial velocity

a is the acceleration

The jet in the problem has, taking east as positive direction:

u = +16 m/s  is the initial velocity

a=+3 m/s^2  is the acceleration

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b. 310 m

The displacement of the jet can be found using another suvat equation

s=ut+\frac{1}{2}at^2

where

s is the displacement

u is the initial velocity

a is the acceleration

t is the time

For the jet in this problem,

u = +16 m/s  is the initial velocity

a=+3 m/s^2  is the acceleration

t = 10 s is the time

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s=(16)(10)+\frac{1}{2}(3)(10)^2=310 m

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Answer:

the velocity of the point P located on the horizontal diameter of the wheel at t = 1.4 s  is   P =  104.04 \hat{i} -314.432 \hat{j}

Explanation:

The free-body  diagram below shows the interpretation of the question; from the diagram , the wheel that is rolling in a clockwise directio will have two velocities at point P;

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where \omega(angular velocity) = \frac{d\theta}{dt} = \frac{d}{dt}(8t^4)

-V_y = 2*32t^3)\\\\\\-V_y = 2*32(1.7^3)\\\\-V_y = 314.432 \ ft/s

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