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siniylev [52]
3 years ago
8

mass and weight are similar, but not the same thing. In which of the following examples would the objects weight change, but mas

s stay the same? A. a child grows taller B. A person goes on a medical diet. C. An astronaut travels from the earth to the moon D. A snowball rolls downhill and picks up snow making it grow
Physics
1 answer:
OverLord2011 [107]3 years ago
7 0

When an astronaut travels from the earth to the moon, her weight changes, but her mass remains constant.  <em>(C ).</em>

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Suppose a horse leans against a wall as in the figure below.
Irina18 [472]

The force the horse and the rider exerts on the wall is equal to the weight combined acting in the opposite direction:

<h3>Force</h3>

Given Data

  • mass of horse and rider = 575kg
  • Force  acting on wall = ??

When a body of mass rests on a surface, it exerts a force equal to the weight of the mass but opposite in direct on the mass/object

hence the force is computed as

Force = mass * acceleration

Force = 575 * 9.81

Force = 5640.75N

Learn more about force here:

brainly.com/question/12970081

8 0
3 years ago
Which shows the correct lens equation? The inverse of f equals the inverse of d Subscript o Baseline times the inverse of d Subs
musickatia [10]

Answer:

The inverse of f equals the inverse of d Subscript o Baseline plus the inverse of d Subscript I Baseline.

Explanation:

The lens equation shows the relation among focal length of the lens, image distance and object distance. It can be expressed as:

  \frac{1}{f} = \frac{1}{d_{o} } + \frac{1}{d_{I} }

where: f is the focal length of the lens, d_{o} is the object distance to the lens and d_{I} is the image distance to the lens.

The lens equation can be used to determine the unknown value among the variables f , d_{o} and d_{o}.

6 0
3 years ago
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A magnetically soft material is placed in a strong magnetic field. What is the most likely outcome?
Svet_ta [14]

D-It will become a temporary magnet because the domains will easily realign.

9 0
3 years ago
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There is a 50 g sample of Ra-229. It has a half-life of 4 minutes.
Sloan [31]

Via half-life equation we have:


A_{final}=A_{initial}(\frac{1}{2})^{\frac{t}{h} }


Where the initial amount is 50 grams, half-life is 4 minutes, and time elapsed is 12 minutes.  By plugging those values in we get:

A_{final}=50(\frac{1}{2})^\frac{12}{4}=50(\frac{1}{2})^{3}=50(\frac{1}{8})=6.25g


There is 6.25 grams left of Ra-229 after 12 minutes.

4 0
4 years ago
A solid, horizontal cylinder of mass 18.0 kg and radius 1.70.0 m rotates with an angular speed of 40 rad/s about a fixed vertica
Radda [10]

Answer:39.88 rad/s

Explanation:

Given

mass of cylinder m_1=18 kg

radius R=1.7 m

angular speed \omega =40rad/s

mass of m_2=0.8 kg dropped at r=0.3 m from center

let \omega _2 be the final angular velocity of cylinder

Conserving Angular momentum

L_1=L_2

\left ( \frac{m_1R^2}{2}\right )\omega =\left ( \frac{m_1R^2}{2}+m_2r^2\right )\omega _2

\left ( \frac{18\cdot 1.7^2}{2}\right )\cdot 40=\left ( \frac{18\cdot 1.7^2}{2}+0.8\cdot 0.3^2\right )\omega _2

26.01\times 40=26.082\times \omega _2

\omega _2=39.88 rad/s

3 0
3 years ago
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