Question

How many atoms are there in 3.559*10^-6 mol of krypton?

Answer 1

Answer:

The answer is

$2.143 \times {10}^{18} \: \: atoms$

Explanation:

To find the number of atoms given the number of moles we use the formula

N = n × L

where

N is the number of entities

n is the number of moles

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question

$n = 3.559 \times {10}^{ - 6} \: mol$

Substitute the values into the above formula and solve

That's

$N = 3.559 \times {10}^{ - 6} \times 6.02 \times {10}^{23} \\ = 2.1425 \times {10}^{18}$

We have the final answer as

$N = 2.143 \times {10}^{18} \: \: atoms$

Hope this helps you