Answer:
Sn(C2H3O2)2
Explanation:
C2H3O2 is Acetate
Sn is tin
Acetate has a -1 charge
In order for tin to have a +2 charge, we need two acetates
So we write it as (C2H3O2)2
You just leave Sn blank because of the roman numeral and since it is a transition metal.
So the answer is Sn(C2H3O2)2
Answer:
There will be 0.825 grams of CO2 produced
Explanation:
Step 1: Data given
Mass of water formed = 0.45 grams
Molar mass of water = 18.02 g/mol
Molar mass of CO2 = 44.01 g/mol
Step 2: The balanced equation
C3H8 + 5O2 → 4H2O + 3CO2
Step 3: Calculate moles of water
Number of moles water = mass of water / molar mass water
Number of moles water = 0.45 grams / 18.02 g/mol
Number of moles water = 0.025 moles
Step 4: Calculate moles of CO2
For 1 mol of propane we need 5 moles of O2 to produce 4 moles of H2O and 3 moles of CO2
When 0.025 moles of H2O are produced, we'll get 3/4 * 0.025 = 0.01875 moles of CO2 produced
Step 5: Calculate mass of CO2 produced
Mass of CO2 = moles of CO2 * molar mass of CO2
Mass of CO2 = 0.01875 moles * 44.01 g/mol
Mass of CO2 = 0.825 grams
There will be 0.825 grams of CO2 produced
Chemical Reactions
Chemical changes take place when molecules or elements interact with other elements or molecules to form new chemical compounds. In order for a reaction to take place between molecules and or atoms, these molecules must come into contact with each other.
An example of a chemical reaction can be shown by the reaction of ammonia with hydrogen chloride to form ammonium chloride. This reaction is usually shown by a shorthand method called a chemical equation. The chemical equation for this reaction is...
NH3 + HCl � NH4Cl
This equation does not clearly show what has happened. In order for these two molecules to react, the pair of electrons on nitrogen must collide with the hydrogen atom of the hydrogen chloride on the side exactly opposite of the chlorine atom.
This collision must not only be precise as to the angle of the collision, it must have enough energy to break the bond between the hydrogen atom and the chlorine atom and form a new bond between the hydrogen atom and the nitrogen atom. Energy is released when a bond is formed. If all of these requirements are met, a reaction occurs forming a new compound.

The rate of a chemical reaction depends on all of the above factors. The reaction rate is measured by the change in concentration of one of the reactants or products over a measured period of time.
If some reaction condition is changed, the reaction rate will be changed.
Reaction coordinate diagrams are used to visualize the energy changes in chemical reactions. Some initial energy must be applied to any reaction in order to get the reaction started. This energy is called the energy of activation Ea.
If a reaction releases more energy than it takes to keep it going, it is called an exothermic reaction.

If a reaction requires a constant application of energy to keep it going, it is called an endothermic reaction.

A catalyst is something that, when added to a chemicalreaction, will increase the reaction rate without undergoing a permanent change. Although it appears that only Ea is lowered for a catalyzed reaction, the actual reaction pathway must change due to the involvement of the catalyst with the reactants. The energy released for the reaction remains the same. Catalysts are used extensively in biochemical reactions in order to decrease the energy demands for the animal or plant.

Matter can neither be gained nor lost in a chemical reaction. The number and type of atoms in the reactants must exactly equal the number and types of atoms in the products. The arrangement of the atoms will be different because new compounds are formed. Therefore, we must balance chemical equations with respect to the numbers of all of the atoms that are involved in the reaction.
Answer:
The limiting reacting is O2
Explanation:
Step 1: data given
Number of moles O2 = 21 moles
Number of moles C6H6O = 4.0 moles
Step 2: The balanced equation
C6H6O + 7O2 → 6CO2 + 3H2O
Step 3: Calculate the limiting reactant
For 1 mol C6H6O we need 7 moles O2 to produce 6 moles CO2 and 3 moles H2O
O2 is the limiting reactant. It will completely be consumed (21 moles).
C6H6O is in excess.
For 7 moles O2 we need 1 mol C6H6O
For 21 moles O2 we'll need 21/7 = 3 moles C6H6O
There will remain 4.0 - 3.0 = 1 mol C6H6O
Step 4: calculate products
For 1 mol C6H6O we need 7 moles O2 to produce 6 moles CO2 and 3 moles H2O
For 21 moles O2 we'll have 6/7 * 21 = 18 moles CO2
For 21 moles O2 we'll have 3/7 * 21 = 9 moles H2O
The limiting reacting is O2