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Luba_88 [7]
3 years ago
12

A hot-air balloon is rising upward with a constant speed of 2.85 m/s. When the balloon is 2.50 m above the ground, the balloonis

t accidentally drops a compass over the side of the balloon. How much time elapses before the compass hits the ground
Physics
1 answer:
NISA [10]3 years ago
5 0

Answer:

Explanation:

You have to declare which way is plus -- up or down. I will use down.

vi = - 2.85       The balloon is going up. That is the minus direction.

a = 9.81

d =   2.50 meters  distance in this case is from the object to the ground.

d = vi*t + 1/2 a t^2

-2.50 = -2.85*t + 1/2 * 9.81 * t^2

-2.50 = -2.85*t + 4.905 * t^2           transfer the left to the right.

-4.905 t^2 + 2.85*t + 2.50 = 0

Use the quadratic formula to solve for t.

It turns out that t = 1.06

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If the vehiche has a speed of 24.0 m/s at point a what is the force of the track on the vehicle at this point?
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Question:

A roller-coaster vehicle has a mass of 500 kg when fully loaded with passengers.  If the vehicle has a speed of 20.0 m/s at point A, what is the force exerted by the track on the vehicle at this point?

<em>See attachment</em>

Answer:

33700 Newton

Explanation:

Given

m = 500kg\\v = 24.0m/s\\r=10m

First, we determine the forces acting on mass m.

They are: the force exerted by the track (Fn) and the weight of the vehicle (W)

So, the net force is:

F_{net} = F_n - W

W=mg

So:

F_{net} = F_n - mg

Make Fn the subject

F_n = F_{net} + mg

Fnet is calculated as:

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So:

F_n = F_{net} + mg

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