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3 years ago

I'll give brainliest....

Physics

1 answer:

natka813 [3]3 years ago

5 0

Answer:

x = ~0.1289 m/s^2

Explanation:

We can use one of the kinematic formulas. We see that the equation doesn’t contain the final velocity, so we use the kinematic equation d = v_0t + (1/2)at^2.

Since the train started from rest, the initial velocity, v_0, is 0. Thus, the equation becomes:

d = (1/2)at^2

Note that 5 minutes is 300 seconds and 5.8 km is 5800 m. Substituting the values we are given, we get:

5800 m = (1/2)(x m/s^2)(300 s)^2 = (45000 s^2)(x m/s^2)

Dividing by 45,000 on both sides, we get:

x = ~0.1289 m/s^2

I hope this helps! :)

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A charge Q is transferred from an initially uncharged plastic ball to an identical ball 10.0 cm away. The force of attraction is

victus00 [196]

Answer:

a charge Q is transferred from an initially uncharged

Explanation:

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2 years ago

9. A 5.0 kg block on an inclined plane is acted upon by a horizontal force of 100 N shown in the figure below. The coefficient o

Helga [31]

Answer:

A: The acceleration is 7.7 m/s up the inclined plane.

B: It will take the block 0.36 seconds to move 0.5 meters up along the inclined plane

Explanation:

Let us work with variables and set

$m=5kg\\\\F_H=100N\\\\\mu=0.3\\\\\theta=37^o.$

As shown in the attached free body diagram, we choose our coordinates such that the x-axis is parallel to the inclined plane and the y-axis is perpendicular. We do this because it greatly simplifies our calculations.

Part A:

From the free body diagram we see that the total force along the x-axis is:

$F_{tot}=mg*sin(\theta)+F_s-F_Hcos(\theta).$

Now the force of friction is $F_s=\mu*N,$ where $N$ is the normal force and from the diagram it is $F_y=mg*cos(\theta).$

Thus $F_s=\mu*N=\mu*mg*cos(\theta).$

Therefore,

$F_{tot}=mg*sin(\theta)+\mu*mg*cos(\theta)-F_Hcos(\theta)\\\\=mg(sin(\theta)+\mu*cos(\theta))-F_Hcos(\theta).$

Substituting the value for $F_H,m,\mu, and \:\theta$ we get:

$F_{tot}= -38.63N.$

Now acceleration is simply

$a=\frac{F_H}{m} =\frac{-38.63N}{5kg} =-7.7m/s.$

The negative sign indicates that the acceleration is directed up the incline.

Part B:

$d=\frac{1}{2} at^2$

Which can be rearranged to solve for t:

$t=\sqrt{\frac{2d}{a} }$

Substitute the value of $d=0.50m$ and $a=7.7m/s$ and we get:

$t=0.36s.$

which is our answer.

Notice that in using the formula to calculate time we used the positive value of $a$ , because for this formula absolute value is needed.

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4 years ago

0.0135 kg of steam at 100°C is

lora16 [44]

Answer:

33333.35 kg

Explanation:

I got it right on Acellus, rounded to 33300 sigfigs

8 0

3 years ago

a stone is thrown down off a bridge with a veloctiy of 5.6m/s. What is the velocity afer 3 seconds have passed?

Flura [38]

I think it's 16.8 because you multiply 5.6x3=16.8

6 0

4 years ago

Read 2 more answers

A bowling ball has a weight of 70 Newton’s on earth. What is it’s mass on earth? What’s it mass on the moon?

AnnyKZ [126]

Weight = (mass) x (gravity)

70 N = (mass) x (9.8 m/s²)

Divide each side by (9.8 m/s²) , and you have

mass = 70 N / 9.8 m/s² = 7.14 kg.
___________________________

Mass on the moon:

Mass doesn't change. It's a number that belongs to the bowling ball,
no matter where the ball goes. If the mass of the bowling ball is 7.14 kg
anywhere, then it's 7.14 kg everywhere ... on Earth, on the moon, on Mars, rolling around in the trunk of my car, or floating in intergalactic space.

However, WEIGHT depends on the gravity wherever the ball happens to be
at the moment.

The acceleration of gravity on the moon is 1.622 m/s².
So the WEIGHT of the ball on the moon is

(7.14 kg) x (1.622 m/s²) = 11.58 Newtons

That's only about 16% of its weight on Earth.

3 0

3 years ago