Niagara Falls is 51 meters high. If you dropped a ball off the ledge, how much time would it take it to hit the water?

When firing a handgun, how far should you hold it from your body?

olga55 [171]

Answer:

Far away as your hand takes you

6 0

3 years ago

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Interactive Solution 6.39 presents a model for solving this problem. A slingshot fires a pebble from the top of a building at a

slava [35]

Answer:

Given that

u = 13 m/s

h= 23 m

a) horizontally

We know that acceleration due top gravity is in vertical direction.

v²=u'²+ 2 g h ( u'= 0 )

v² = 2 x 9.81 x 23

v= 21.24 m/s ( vertical direction)

In the horizontal direction

u = 13 m/s

The resultant velocity

V²=v²+u²

V²=21.24²+13²

V= 24.91 m/s

(b) vertically straight up

u= 13 m/s

v²=u²+ 2 g h

v²=13²+ 2 x 9.81 x 23

v= 24.91 m./s

c)vertically straight down.

u= 13 m/s

v²=u²+ 2 g h

v²=13²+ 2 x 9.81 x 23

v= 24.91 m./s

4 0

3 years ago

A 30.0-Î¼F capacitor is connected to a 49.0-Î© resistor and a generator whose rms output is 30.0 V at 60.0 Hz. (a) Find the rms

Natali5045456 [20]

Explanation:

Given that,

Capacitor = 30μC

Resistor = 49.0Ω

Voltage = 30.0 V

Frequency = 60.0 Hz

We need to calculate the impedance

Using formula of impedance

$Z=\sqrt{R^2+X_{c}^2}$ .....(I)

We need to calculate the value of $X_{c}$

Using formula of $X_{c}$

$X_{c}=\dfrac{1}{2\pi f c}$

$X_{c}=\dfrac{1}{2\times\pi\times60.0\times30\times10^{-6}}$

$X_{c}=88.42\ \Omega$

Put the value of $X_{c}$ into the formula of impedance

$Z=\sqrt{(49.0)^2+(88.42)^2}$

$Z=101.08\ \Omega$

(a). We need to calculate the rms current in the circuit

Using formula of rms current

$I_{rms}=\dfrac{V}{Z}$

$I_{rms}=\dfrac{30.0}{101.08}$

$I_{rms}=0.30\ A$

The rms current in the circuit is 0.30 A.

(b). We need to calculate the rms voltage drop across the resistor

Using formula of rms voltage

$V_{rms}=I_{rms}\times R$

Put the value into the formula

$V_{rms}=0.30\times49.0$

$V_{rms}=14.7\ V$

The rms voltage drop across the resistor is 14.7 V

(c). We need to calculate the rms voltage drop across the capacitor

Using formula of rms voltage

$V_{rms}=I_{rms}\times X_{C}$

$V_{rms}=0.30\times88.42$

$V_{rms}=26.53\ V$

The rms voltage drop across the capacitor is 26.53 V.

Hence, This is the required solution.

4 0

3 years ago

According to the law of conservation of energy,

vodka [1.7K]

According to the law of conservation of energy,

A. an object loses most of its energy as friction

<u>B. the total amount of energy for a system stays the same</u>

Energy is never lost due to the law of conservation

C. the potential energy of an object is always greater than its kinetic energy

D. the kinetic energy of an object is always greater than its potential energy

8 0

3 years ago

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A 10 kilogram sled is pulled across a frictionless surface with a force of 50 newtons for a distance of 10 meters. The pull is a

Gala2k [10]

Answer:

The power will be "250 watt". A further explanation is given below.

Explanation:

The given values are:

Force,

F = 50 N

Displacement,

d = 20 m

Time,

t = 2.0 seconds

Whenever the block is pulled, the angle will be "0" i.e., Cos0° = 1

Now,

The work will be:

= $Force\times displacement\times \Theta$

On substituting the given values, we get

= $50\times 10\times Cos0^{\circ}$

= $50\times 10\times 1$

= $500 \ Newton$

Now,

The Power will be:

= $\frac{Work \ done}{time}$

= $\frac{500}{2.0}$

= $250 \ watt$

8 0

3 years ago