Answer:
r = 0.119 m
Explanation:
distance (d) = 1.6 mm = 0.0016 m
electric field strength (E) = 2.7 x 10^{6} N/C
charge (Q) = -1.07 μC = -1.07 x 10^{-6} C
permitivity of vacuum = 8.8542 x 10^{-12} C^{2}/N
find the radius of the plate required
- lets first find the voltage
voltage (V) = E x d
voltage (V) = 2.7 x 10^{6} x 0.0016 = 4320 V
- lets also find capacitance (C) = Q/V
C = -1.07 x 10^{-6} / 4320 = 2.47 x 10^{-10} F
- the value of capacitance (C) is also = E₀A / d
we can rearrange the equation above to have our area (A) = Cd/ E₀
A =
A = 0.0446 m^{2}
- Area (A) = π x
r =
r =
r = 0.119 m
I believe the answer is A.
Ah for this problem you are thinking quite a bit hard on. The problem is actually simpler than it looks. The problem states that a bike travels at a constant speed of 3.1 m/s for 6 s and asks how far will it go?. To figure this out you simply need to take 3.1 times 6 s because every second the bike travels 3.1 m. So the answer to this problem would be 18.6 m