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WINSTONCH [101]
3 years ago
13

A 5kg rock is lifted 2m. Find the amount of work done. ​

Physics
1 answer:
lianna [129]3 years ago
5 0

Answer:

98J

Explanation:

Given parameters:

Mass of rock  = 5kg

Height = 2m

Unknown:

Work done  = ?

Solution:

The amount of work done is given as:

 Work done  = Force x distance

 Work done = Weight x height

  Work done  = mgH

Now insert the parameters and solve;

 Work done  = 5 x 9.8 x 2 = 98J

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When summer changes to fall, what seasonal changes do plants experience? (IGNORE HIGHLIGHTED ANSWER)
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Answer:

C

Explanation:

There is a decrease in temperature and daylight and plants produce less food.

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*Quick Reminder: If this is an assignment from homeschool/school, please don't forget to rephrase/summarize/reference from this answer. Keep in mind no plagiarism is allowed in school. And please don't plagiarize this answer. Thanks!*

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In addition to possibly releasing harmful chemicals in the environment, mining is considered
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In addition to possibly releasing harmful chemicals in the environment, mining is considered B. The most dangerous job in the United States.
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A transformer consisting of two coils wrapped around an iron core is connected to a generator and a resistor (Resistor is connec
V125BC [204]

Answer:

The peak emf of the generator is 40.94 V.

Explanation:

Given that,

Number of turns in primary coil= 11

Number of turns in secondary coil= 18

Peak voltage = 67 V

We nee to calculate the peak emf

Using relation of number of turns and emf

\dfrac{N_{1}}{N_{2}}=\dfrac{E_{1}}{E_{2}}

E_{1}=\dfrac{N_{1}}{N_{2}}\times E_{2}

Where, N₁ = Number of turns in primary coil

N₂ = Number of turns in secondary coil

E₂ = emf across secondary coil

Put the value into the formula

E_{1}=\dfrac{11}{18}\times67

E_{1}=40.94\ V

Hence, The peak emf of the generator is 40.94 V.

4 0
3 years ago
a large sphere is on a horizontal field on a sunny day. at a certain time the shadow reaches out a distance of 10 m from the poi
Mars2501 [29]

The radius of the sphere in meters is ,r = 10\sqrt{5} -20

Think about the angle the ground and the shadow make. Since the sun's beams are parallel, the angle created by the stick's shadow is also equal. Since the stick is 1 m high and its shadow is 2 m long, we know that the stick's angle is arctan 1/2. Therefore, by thinking of a right-angled triangle,

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Since, tan (θ/2) = 1-cos(θ) / sin(θ)

we find that,

r/10 = \sqrt{5} -2

Hence, r = 10\sqrt{5} -20

So, the radius of the sphere in meters is ,r = 10\sqrt{5} -20

Learn more about radius (r) of the sphere here;

brainly.com/question/14100787

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5 0
1 year ago
What is the term for the force exerted by an object when it is pushed by another object?
kolezko [41]
Action-reaction pairs.

This is in reference to Newton’s second law of motion.
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3 years ago
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