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Anna [14]
3 years ago
11

Hdkshshgsksisbsgshsbisheghs be iwhghhfhjdjjh

Physics
1 answer:
zlopas [31]3 years ago
6 0

Answer:

dsfcwisienruyoiqnpu3p is enicuwyeiourcbt84ru

Explanation:

uqyoeyriuobyeriuov uvry84bvruoiby4roybvoiur ryvw8rvby82yrbiuo3

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Divers found two substances on the bottom of the ocean. At room temperature, both substances are liquid. Scientists then transfe
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Human centrifuges are used to train military pilots and astronauts in preparation for high-g maneuvers. A trained, fit person we
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(a) 4.14 rad/s^2

The relationship beween centripetal acceleration and angular speed is

a=\omega^2 r

where

\omega is the angular speed

r is the radius of the circular path

Here we gave

a = 9g = 88.2 m/s^2 is the centripetal acceleration

r = 5.15 m is the radius

Solving for \omega, we find:

\omega = \sqrt{\frac{a}{r}}=\sqrt{\frac{88.2 m/s^2}{5.15 m}}=4.14 rad/s^2

(b) 21.3 m/s

The relationship between the linear speed and the angular speed is

v=\omega r

where

v is the linear speed

\omega is the angular speed

r is the radius of the circular path

In this problem we have

\omega=4.14 rad/s

r = 5.15 m

Solving the equation for v, we find

v=(4.14 rad/s)(5.15 m)=21.3 m/s

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3 years ago
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Your answer is B

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