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Anna [14]
3 years ago
11

Hdkshshgsksisbsgshsbisheghs be iwhghhfhjdjjh

Physics
1 answer:
zlopas [31]3 years ago
6 0

Answer:

dsfcwisienruyoiqnpu3p is enicuwyeiourcbt84ru

Explanation:

uqyoeyriuobyeriuov uvry84bvruoiby4roybvoiur ryvw8rvby82yrbiuo3

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An ideal air-filled parallel-plate capacitor has round plates and carries a fixed amount of equal but opposite charge on its pla
dusya [7]

Answer:

C). U_f = \frac{U_0}{2}

Explanation:

As we know that capacitance of a given capacitor is

C = \frac{\epsilon_0 A}{d}

now we know that energy stored in the capacitor plates

U_0 = \frac{Q^2}{2C}

here if all the dimensions of the capacitor plate is doubled

then in that case

C' = \frac{\epsilon_0 (4A)}{2d}

here area becomes 4 times on doubling the radius and the distance between the plates also doubles

So new capacitance is now

C' = 2C

so capacitance is doubled

now the final energy stored between the plates of capacitor is given as

U_f = \frac{Q^2}{2C'}

so the final energy is

U_f = \frac{Q^2}{4C}

U_f = \frac{U_0}{2}

4 0
3 years ago
The amount of energy that remains after the amount of energy used for respiration is subtracted from the total is called
lawyer [7]

Answer:Gibb's free energy

Explanation:

The Free energy change describes the amount of energy that is available in any system to do work. It is often designated with the symbol G

4 0
3 years ago
What process is used in this example? You have learned that all living things use energy. Your dog is a living thing. She must u
oksano4ka [1.4K]
Option B.) Deductive Reasoning
8 0
3 years ago
A catapult launches a test rocket vertically upward from a well, giving the rocket an initial speed of 80.0 m/s at ground level.
BARSIC [14]

Answer:

There is an interval of 24.28s in which the rocket is above the ground.

Explanation:

y_{i}=0m

v_i=80\frac{m}{s}

a=4\frac{m}{s^2}

y_{e}=1000m

g=9.8\frac{m}{s^2}

From Kinematics, the position y as a function of time when the engine still works will be:

y(t)=v_it+\frac{1}{2}at^2

At what time the altitud will be y_{e}=1000m?

v_it+\frac{1}{2}at^2=y_{e} ⇒ \frac{1}{2}at^2+v_it-y_{e}=0

Using the quadratic formula: t_1=10s.

How much time does it take for the rocket to touch the ground? No the function of position is:

y(t)=y_{e}+v_et-\frac{1}{2}gt^2

Where our new initial position is y_{max}, the velocity when the engine breaks is v_e=v_i+at=120\frac{m}{s} and the only acceleration comes from gravity (which points down).

Now, when the rocket tounches the ground:

y_{e}+v_et-\frac{1}{2}gt^2=0

Again, using the quadratic ecuation:

t_2=24.49s

Now, the total time from the moment it takes off and the moment it tounches the ground will be:

t_T=t_1+t_2=34.49s.

6 0
3 years ago
a planes average speed between two cities is 600 km/hrs. if the trip takes 2.5 its how for does the plane fly
Nastasia [14]
It’s 600 x 2.5 which is 1500. So the plane flies about 1500km in 2.5 hrs.
4 0
2 years ago
Read 2 more answers
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